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Mkey [24]
3 years ago
5

Food cook faster when placed in a pressure cooker. This is because the pressure on the surface of the water is (space) the atmos

pheric pressure, and the boiling point of water is (space) normal.
Physics
2 answers:
andrezito [222]3 years ago
8 0
Food coosk faster when placed in a pressure cooker. This is because the pressure on the surface of the water is (higher) the atmospheric pressure, and the boiling point of water is (lower than) normal.
taurus [48]3 years ago
5 0
Is this a question? i doun understand what you are saying
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What is the kinetic energy of a 620.0 kg roller coaster moving with a velocity of 9.00 m/s?
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Ek = 1/2 x m x v ²

1/2 x 620.0 x 9.00 ² = 25,100
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A 69 kg zebra is traveling 7 m/s east. What is the zebra’s momentum? kg-m/s
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2 years ago
After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 49.0 cm . The explorer finds that
iren2701 [21]

Answer: g = 10.0 m/s/s

Explanation:

For a simple pendulum, provided that the angle between the lowest and highest point of  his trajectory be small, the oscillation period is given by the following expression:

T = 2π √L/g , where L = pendulum length, g= accelleration of gravity.

We can also define the period, as the time needed to complete a full swing, so from the measured  values, we can conclude the following :

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g = 4 π² L / T² = 4π². 0.49 m / (1.39)² = 10.0 m/s/s

7 0
3 years ago
A charge of 7.2 × 10-5 C is placed in an electric field with a strength of 4.8 × 105 StartFraction N over C EndFraction. If the
barxatty [35]

Answer:

2.2 meters

Explanation:

Potential energy, PE created by a charge, q at a radius r from the charge source, Q,  is expressed as:

KE=\frac{kQq}{r}\     \ \ \ \ \ \ ...i

k is Coulomb's constant.

#The electric field,E at radius r is expressed as:

E=\frac{kQ}{r^2}\ \ \ \ \ \ \ \ \ \ ...ii

From i and ii, we have:

KE=Eqr

r=(KE)/Eq

#Substitute actual values in our equation:

r=\frac{75J}{(7.2\times 10^{-5}C)(4.8\times 10^5 V/m)}\\\\=2.1701\approx2.2\ m

Hence, the distance between the charge and the source of the electric field is 2.2 meters

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2 years ago
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did you tried first if you did I can help

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