Answer:
Rounded to three significant figures:
(a) .
(b) .
Explanation:
Consider a double-slit experiment where a wide beam of monochromatic light arrives at a filter with a double slit. On the other side of the filter, the two slits will appear like two point light sources that are in phase with each other. For each point on the screen, "path" refers to the length of the segment joining that point and each of the two slits. "Path difference" will thus refer to the difference between these two lengths.
Let denote a natural number (.) In a double-split experiment of a monochromatic light:
- A maximum (a bright fringe) is produced when light from the two slits arrive while they were in-phase. That happens when the path difference is an integer multiple of wavelength. That is: .
- Similarly, a minimum (a dark fringe) is produced when light from the two slits arrive out of phase by exactly one-half of the cycle. For example, The first wave would be at peak while the second would be at a crest when they arrive at the screen. That happens when the path difference is an integer multiple of wavelength plus one-half of the wavelength: .
<h3 /><h3>Maxima</h3>
The path difference is at a minimum (zero) at the center of the screen between the two slits. That's the position of the first maximum- the central maximum, a bright fringe where in .
The path difference increases while moving on the screen away from the center. The first order maximum is at where .
Similarly, the second order maximum is at where . For the light in this question, at the second order maximum: .
- Central maximum: , such that .
- First maximum: , such that .
- Second maximum: , such that .
<h3>Minima</h3>
The dark fringe closest to the center of the screen is the first minimum. at that point.
Add one wavelength to that path difference gives another dark fringe- the second minimum. at that point.
- First minimum: , such that .
- Second minimum: , such that .
For the light in this question, at the second order minimum: .
Answer:
The magnitude of the net current = 18 A.
Direction of the net current is along the negative z axis.
Explanation:
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<u><em>Given:</em></u>
- Number of electrons flow through the given cross section,
- Number of electrons flow through the given cross section,
- Time interval for which the electrons and protons flow,
The current through a cross section is defined as the amount of charge passing through that cross section in unit time.
We know,
Charge on an electron,
Charge on a proton,
Therefore,
The amount of charge flowing due to electrons is given by
The amount of charge flowing due to protons is given by
The current flowing through the cross section because of the electrons is given as:
The negative sign shows that the current is due to the flow of negative charge, and the direction of current is always opposite to that of flow of negative charge i.e., electrons.
Thus, the direction of this current is along the negative z direction.
The magnitude of this current = 12 A.
The current flowing through the cross section because of the protons is given as:
The direction of this current is same as that of electrons,
The directions of the currents due to both, the electrons and the protons are along the negative z direction, therefore the magnitude of the net current is given as:
When saturated air is cooled, it simply reaches its dew point. Dew point is simply the temperature at which dew begins to form.
Dew point of saturated air is already pre-determined by how much water vapor the air contains. A state of saturation exists when the air is holding the maximum amount of water vapor possible at the existing temperature and pressure. The higher the dew point, the higher the moisture content of the air. Cooling does not change the dew point of saturated air, rather its the level of saturation.
So if the air has more moisture, dew will form at a higher temperature and vice versa, but dew point is NEVER EVER GREATER than the air temperature.