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11Alexandr11 [23.1K]
3 years ago
10

What is actually creating the light in the light bulb?

Physics
2 answers:
Strike441 [17]3 years ago
6 0

The light in the light bulb is simply the resultant of photon emission through a thin filament often made of tungsten.

<u>Explanation :</u>

Explaining the structure, a light bulb is simply composed of a metal base with two metal contacts. These contacts are attached to the current conducting wires that are attached to a thin filament often made of Tungsten.  

The whole system is enclosed within a light bulb filled with an inert gas Argon. On connecting the light bulb to the electric supply, the current flows through the wires and heats up the filament that emits photons, containing visible light energy. This is how we get a lighted bulb.

The invention of a light bulb has always been one of the biggest inventions in the world of science and technology that has lightened up not only the world but the lives. All credit goes to Sir Thomas Alva Edison and Sir Joseph Swan.

gizmo_the_mogwai [7]3 years ago
3 0
Positive and negative charge
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Manuel traveled 3 hours nonstop to​ Mexico, a total of 197 miles. He took a train part of the​ way, which averaged 70​mph, and t
Anton [14]

Answer:

1.7 hours

Explanation:

Time taken in the journey = 3 hours

Distance of the entire journey = 197 miles

Distance travelled on train = x

Distance travelled on bus = 197-x

Average speed of train = 70 mph

Average speed of bus = 60 mph

Time = Distance / Speed

\frac{x}{70}+\frac{197-x}{60}=3\\\Rightarrow \frac{6x+1379-7x}{420}=3\\\Rightarrow -x+1379=3\times 420\\\Rightarrow -x=1260-1379\\\Rightarrow x=119\ miles

Distance travelled by train = 119 miles

Time taken on train = 119 / 70 = 1.7 hours

Manuel spent 1.7 hours on the​ train

7 0
3 years ago
How do I know what kinematic equations to use when solving a question?
olganol [36]

Explanation:

There are 5 kinematic equations, and 5 variables.

Each question will give you 3 variables and ask you to solve for a fourth.

To determine which equation to use, look at which variable is <em>not</em> included in the problem.

For example, if the question does not include time, then you need to use a kinematic equation that does not have t in it.  That would be:

v² = v₀² + 2aΔx

Or, if the question does not include the final velocity, then you need a kinematic equation that does not have v in it.  That would be:

Δx = v₀ t + ½ at²

5 0
3 years ago
1. Express the following quantities in scientific notation.
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5.8x10^3
3.02x10^8
4.5x10^5
8.6x10^10
4 0
4 years ago
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A 1 kg mass is attached to a spring with spring constant 7 Nt/m. What is the frequency of the simple harmonic motion? What is th
Scorpion4ik [409]

1. 0.42 Hz

The frequency of a simple harmonic motion for a spring is given by:

f=\frac{1}{2\pi}\sqrt{\frac{k}{m}}

where

k = 7 N/m is the spring constant

m = 1 kg is the mass attached to the spring

Substituting these numbers into the formula, we find

f=\frac{1}{2\pi}\sqrt{\frac{7 N/m}{1 kg}}=0.42 Hz

2. 2.38 s

The period of the harmonic motion is equal to the reciprocal of the frequency:

T=\frac{1}{f}

where f = 0.42 Hz is the frequency. Substituting into the formula, we find

T=\frac{1}{0.42 Hz}=2.38 s

3. 0.4 m

The amplitude in a simple harmonic motion corresponds to the maximum displacement of the mass-spring system. In this case, the mass is initially displaced by 0.4 m: this means that during its oscillation later, the displacement cannot be larger than this value (otherwise energy conservation would be violated). Therefore, this represents the maximum displacement of the mass-spring system, so it corresponds to the amplitude.

4. 0.19 m

We can solve this part of the problem by using the law of conservation of energy. In fact:

- When the mass is released from equilibrium position, the compression/stretching of the spring is zero: x=0, so the elastic potential energy is zero, and all the mechanical energy of the system is just equal to the kinetic energy of the mass:

E=K=\frac{1}{2}mv^2

where m = 1 kg and v = 0.5 m/s is the initial velocity of the mass

- When the spring reaches the maximum compression/stretching (x=A=amplitude), the velocity of the system is zero, so the kinetic energy is zero, and all the mechanical energy is just elastic potential energy:

E=U=\frac{1}{2}kA^2

Since the total energy must be conserved, we have:

\frac{1}{2}mv^2 = \frac{1}{2}kA^2\\A=\sqrt{\frac{m}{k}}v=\sqrt{\frac{1 kg}{7 N/m}}(0.5 m/s)=0.19 m

5. Amplitude of the motion: 0.44 m

We can use again the law of conservation of energy.

- E_i = \frac{1}{2}kx_0^2 + \frac{1}{2}mv_0^2 is the initial mechanical energy of the system, with x_0=0.4 m being the initial displacement of the mass and v_0=0.5 m/s being the initial velocity

- E_f = \frac{1}{2}kA^2 is the mechanical energy of the system when x=A (maximum displacement)

Equalizing the two expressions, we can solve to find A, the amplitude:

\frac{1}{2}kx_0^2 + \frac{1}{2}mv_0^2=\frac{1}{2}kA^2\\A=\sqrt{x_0^2+\frac{m}{k}v_0^2}=\sqrt{(0.4 m)^2+\frac{1 kg}{7 N/m}(0.5 m/s)^2}=0.44 m

6. Maximum velocity: 1.17 m/s

We can use again the law of conservation of energy.

- E_i = \frac{1}{2}kx_0^2 + \frac{1}{2}mv_0^2 is the initial mechanical energy of the system, with x_0=0.4 m being the initial displacement of the mass and v_0=0.5 m/s being the initial velocity

- E_f = \frac{1}{2}mv_{max}^2 is the mechanical energy of the system when x=0, which is when the system has maximum velocity, v_{max}

Equalizing the two expressions, we can solve to find v_{max}, the maximum velocity:

\frac{1}{2}kx_0^2 + \frac{1}{2}mv_0^2=\frac{1}{2}mv_{max}^2\\v_{max}=\sqrt{\frac{k}{m}x_0^2+v_0^2}=\sqrt{\frac{7 N/m}{1 kg}(0.4 m)^2+(0.5 m/s)^2}=1.17 m/s m

4 0
3 years ago
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When all parts of a circuit are composed of conducting materials, the circuit is said to be
Korolek [52]
Closed is the correct answer :)
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