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3 years ago

How far will a car travel from a standing start if it accelerates at 4.0m/s2 for 9.0 seconds

Physics

1 answer:

ehidna [41]3 years ago

5 0

Answer:

4*9 = 36 m/sec at 9 seconds. The average speed is (0 + 36)/2 = 18 .

Explanation:

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1. Question

Paraphin [41]

All of the forces listed are correct. There are 4 presently known forces.
Second question os B. the Lorentz force. It's given by
F=q(E+VxB) where q is the electric charge, E is the electric field, V is the particle's velocity vector, B is the magnetic flux density, and "x" represents the vector cross product.

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3 years ago

Does the planet exert a torque on the meteoroid with respect to the center of mass of the planet? Why or why not?

ra1l [238]

Answer:

yes

Explanation:

because the planet exerts a centripetal force on the meteorold

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3 years ago

How much force is needed to accelerate a 3kg book in 15m/s

kotegsom [21]

F=M×A
F=3 ×15
F=45N
so the force is 45 N

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3 years ago

Suppose that a spiral galaxy is located at the center of a spherically symmetric dark matter halo

Novosadov [1.4K]

To solve the problem it is necessary to use the concepts of Orbital Speed considering its density, and its angular displacement.

In general terms the Orbital speed is described as,

$V_{orbit} = \sqrt{\frac{G\rho 4\pi r^3}{3}}$

PART A) If the orbital speed of a star in this galaxy is constant at any radius, then,

$\frac{4\pi G\rho r}{3} = \frac{v^2}{r}$

$\frac{4\pi G\rho r}{1} = \frac{3v^2}{r}$

$\frac{\rho}{1} = \frac{3v^2}{r^2 4\pi G}$

$\rho = \frac{1}{r^2}$

PART B) This time we have $v=\omega t$ , where $\omega$ is the angular velocity (constant at this case)

$\frac{4\pi G\rho r}{3} = \frac{v^2}{r}$

$\frac{4\pi G\rho r}{3} = \frac{(\omega r)^2}{r}$

$\rho = \frac{3\omega r}{4\pi Gr}$

$\rho = \frac{3\omega^2}{4\pi G} \propto constant$

PART C) If the total mass interior to any radius r is a constant,

$\frac{4\pi G\rho r}{3} = \frac{v^2}{r}$

$\frac{GM}{r^2}=\frac{v^2}{r}$

$v = \sqrt{\frac{GM}{r}}$

$v= \sqrt{\frac{1}{r}}$

3 0

4 years ago

What is the wavelength of a 2.2 mhz ultrasound wave traveling through aluminum? assume that the speed of sound in aluminum is 51

Eva8 [605]

The frequency of a wave is equal to the linear speed divided the wavelength. so in equation form.
f = v / l
so the wavlength
l = v / f
where f is the frequency
v iss the linear speed
l is the wavelength

l = ( 5100 m/s ) / ( 2.2 Mhz ) ( 10^6 hz / 1 Mhz )
f = 0.0023 m
f = 2.3 mm

7 0

3 years ago