Answer:
H 13.8mol CO2
Explanation:
we know that per 1 mol there is 6.022x10^23 molecules
so divide 8.23x10^22/ AVG # ( # above) we get 13.8mol of CO2 not to be confused with A
Answer:The functional groups in an organic compound can frequently be deduced from its infrared absorption spectrum. A compound, C5H10O2, exhibits strong, broad absorption across the 2500-3200 cm^1 region and an intense absorption at 1715 cm'^-1. Relative absorption intensity: (s)=strong, (m)-medium, (w) weak. What functional class(cs) docs the compound belong to List only classes for which evidence is given here. Attach no significance to evidence not cited explicitly. Do not over-interpret exact absorption band positions. None of your inferences should depend on small differences like 10 to 20 cm^1. The functional class(es) of thla compound is(are) alkane (List only if no other functional class applies.) alkene terminal alkyne internal alkyne arene alcohol ether amine aldehyde or ketone carboxylic acid ester nitr
Answer:
[AB] is 0.65 M
Explanation:
Let the concentration of AB after 10.3s be y
Rate = ky^2 = change in concentration of AB/time
k = 0.2 L/mol.s.
Change in concentration of AB = 1.5 - y
Time = 10.3s
0.2y^2 = 1.5-y/10.3
0.2y^2 × 10.3 = 1.5 - y
2.06y^2 = 1.5 - y
2.06y^2 + y - 1.5 = 0
The value of y must be positive and is obtained using the quadratic formula
y = [-1 + sqrt(1^2 -4×2.06×-1.5)]/2(2.06) = [-1 + sqrt(13.36)]/4.12 = 2.66/4.12 = 0.65 M
Atoms are the smallest bits of ordinary matter and are made from particles called protons, neutrons and electrons while a An element is a substance that is made entirely from one type of atom
Answer:
48 000 cm^2
Explanation:
8000 1cm cubes
each 1 cm cube side is 1 cm^2 and there are six sides to the cube , so each cube has 6 cm^2 surface area
and there are 8000 of them 8000 * 6 cm^2 = 48 000 cm^2