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Dvinal [7]
3 years ago
11

During electrophilic aromatic substitution, a resonance-stabilized cation intermediate is formed. Groups, already present on the

benzene ring, that direct ortho/para further stabilize this intermediate by participating in the resonance delocalization of the positive charge. Assume that the following group is present on a benzene ring at position 1 and that you are brominating the ring at positon 4. Draw the structure of the resonance contributor that shows this group actively participating in the charge delocalization.
-----OCH3
Chemistry
1 answer:
DIA [1.3K]3 years ago
5 0

Answer:

See explanation and image attached

Explanation:

Aromatic compounds undergo electrophilic aromatic substitution reactions in which the aromatic ring is maintained.

Substituted benzenes may be more or less reactive towards electrophilic aromatic substitution than benzene depending on the nature of the substituent present in the ring.

Substituents that activate the ring towards electrophilic substitution such as -OCH3 are ortho-para directing.

The major products of the bromination of anisole are p-bromoanisole and o-bromoanisole. The resonance structures leading to these products are shown in the image attached.

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4 years ago
What is the pressure exerted by a force of 15.0 N over an area of 0.00372 m^2 ?
aleksandrvk [35]

Explanation:

Pressure = Force/Area

therefore,

P = 15/0.00372

= 4.03 X10^³N/m²

6 0
2 years ago
An object has a density of 1.8 g/mL and a mass of 14 g. What is the volume of the object
lesya692 [45]

Answer:

0.13 cm^3

Explanation:

Volume = Mass/ density

1.8 g/ml / 14g = 0.128571429

Both numbers have 2 significant digits.

With that, the answer rounds to 0.13

The final answer is 0.13 cm(don't forget the units for volume)

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4 0
3 years ago
A solar heating specialist is considering paraffin (Cp = 2.90 J/g O C) as a storage material for heat. How many kg of paraffin w
Stels [109]

Answer:

Mass of paraffin that would be needed to collect the amount of energy as 4.73 x 10³ kg of water is 6.85 * 10³ kg

Explanation:

Specific heat capacity of paraffin, Cp = 2.90 J/g.°C = 2900 J/kg.°C

Specific heat capacity of water = 4.20 J/g.°C = 4200 J/kg.°C

Amount of heat energy that can be stored by 4.73 * 10³ kg of water heated through a degree rise in temperature can be calculated as below:

Using  H = mCpθ where m is mass of substance, Cp is specific heat capacity and θ is temperature change

H = 4.73 * 10³ kg * 4200 J/kg.°C * 1°C

H = 19866000 J

Mass of paraffin that would be needed to collect the amount of energy as 4.73 x 10 3 kg of water for a degree rise in temperature is calculated as follows:

H = mCpθ

19866000J = m * 2900 J/kg.°C * 1°C

m = 19866000J / 2900 J/kg

m = 6850.34 kg = 6.85 * 10³ kg

Therefore, mass of paraffin that would be needed to collect the amount of energy as 4.73 x 10³ kg of water is 6.85 * 10³ kg

7 0
3 years ago
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