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Dvinal [7]
2 years ago
11

During electrophilic aromatic substitution, a resonance-stabilized cation intermediate is formed. Groups, already present on the

benzene ring, that direct ortho/para further stabilize this intermediate by participating in the resonance delocalization of the positive charge. Assume that the following group is present on a benzene ring at position 1 and that you are brominating the ring at positon 4. Draw the structure of the resonance contributor that shows this group actively participating in the charge delocalization.
-----OCH3
Chemistry
1 answer:
DIA [1.3K]2 years ago
5 0

Answer:

See explanation and image attached

Explanation:

Aromatic compounds undergo electrophilic aromatic substitution reactions in which the aromatic ring is maintained.

Substituted benzenes may be more or less reactive towards electrophilic aromatic substitution than benzene depending on the nature of the substituent present in the ring.

Substituents that activate the ring towards electrophilic substitution such as -OCH3 are ortho-para directing.

The major products of the bromination of anisole are p-bromoanisole and o-bromoanisole. The resonance structures leading to these products are shown in the image attached.

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Answer:

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All matter is composed of extremely small particles called atoms. All atoms of a given element are identical in size, mass,

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The weight of the plane is  (mass) x (acceleration of gravity).

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A student has a balloon with a volume of 2.5 liters that contains 4.0 moles of air. The ballon has a small leak, allowing one mo
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Answer:

1.9 L

Explanation:

Step 1: Given data

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  • Final number of moles of air (n₂): 3.0 mol
  • Final volume of the balloon (V₂): ?

Step 2: Calculate the final volume of the balloon

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V₁ / n₁ = V₂ / n₂

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6 0
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At a particular temperature, the solubility of He in water is 0.080 M when the partial pressure is 1.7 atm. What partial pressur
fenix001 [56]

At a particular temperature, the solubility of He in water is 0.080 M when the partial pressure is 1.7 atm. 4.25 atm is the  partial pressure of He would give a solubility of 0.200 M.

<h3>What is Henry's Law ?</h3>

Henry's Law is a gas law states that at a constant temperature the amount of gas that dissolved in a liquid is directly proportional to the partial pressure of that gas.

<h3>What is relationship between Henry's Law constant and Solubility ?</h3>

The solubility of gas is directly proportional to partial pressure.

It is expressed as:

S_{\text{gas}} = K_{H} P_{\text{gas}}

where,

S_{\text{gas}} = Solubility of gas

K_{H} = Henry's Law constant

P_{\text{gas}} = Partial pressure of gas

Now put the values in above expression we get

S_{\text{gas}} = K_{H} P_{\text{gas}}

0.080M = K_{H} × 1.7 atm

K_{H} = \frac{0.080\ M}{1.7\ \text{atm}}

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Now we have to find the partial pressure of He

S_{\text{gas}} = K_{H} P_{\text{gas}}

0.200 M = 0.047 M/atm × P_{\text{gas}}

P_{\text{gas}} = \frac{0.200 M}{0.047\ \text{M/atm}}

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Thus from the above conclusion we can say that At a particular temperature, the solubility of He in water is 0.080 M when the partial pressure is 1.7 atm. 4.25 atm is the  partial pressure of He would give a solubility of 0.200 M.

Learn more about the Henry's Law here: brainly.com/question/23204201

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How many protons and electrons are in Hg+
Gala2k [10]

Answer:

There are 80 protons and 80 electrons in Hg+ (Mercury)

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Number of Electrons 80

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Boiling Point 356.58° C

Density 13.456 grams per cubic centimeter

Normal Phase Liquid

Family Transitions Metals

Period Number 6

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