Answer:
y1 = 0.3162
y2 = 0.6838
Explanation:
ok let us begin,
first we would be defining the parameters;
at 25°C;
1-propanol P1° = 20.90 Torr
2-propanol P2° = 45.2 Torr
From Raoults law:
P(1-propanol) = P⁰ × X(1-propanol)
P(1-propanol) = 20.9 torr × 0.45 = 9.405
P(1-propanol) = 9.405 torr
Also P(2-propanol) = P⁰ × X(2-propanol)
P(2-propanol) = 45.2 torr × 0.45
P(2-propanol) = 20.34 torr
but the total pressure = sum of individual pressures
total pressure = 9.405 + 20.34
total pressure = 29.745 torr
given that y1 and y2 represent the mole fraction of each in the vapor phase
y1 = P1 / total pressure
y1 = 9.405/29.745
y1 = 0.3162
Since y1 + y2 = 1
y2 = 1 - y1
∴ y2 = 1 - 0.3162
y2 = 0.6838
cheers, i hope this helps.
Answer:
hi
Explanation:
The mass of the actual tin will remain constant; however I assume you are comparing the mass of the reactant, tin, with the mass of the products. The increase in mass stems from the oxides of tin present due to its reaction with oxygen in the air:
Sn(s) + O2(g) → SnO2(s)
By working out the atomic mass of the tin and the relative formula mass of tin oxide, you can see why there is a mass increase; 119:151. As you can see here, for every 119g of tin reacted, there will be 151g of tin oxide, hence why you think the mass of the tin increased (by 32g).
Hope this helped!
inital velocity (u) should be less