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<u>Answer:</u> The amount of carbon dioxide formed in the reaction is 5.663 grams
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
.....(1)
Given mass of oxygen gas = 8 g
Molar mass of oxygen gas = 32 g/mol
Putting values in equation 1, we get:
For the given chemical equation:
By Stoichiometry of the reaction:
7 moles of oxygen gas produces 4 moles of carbon dioxide
So, 0.25 moles of oxygen gas will produce = of carbon dioxide
Now, calculating the mass of carbon dioxide from equation 1, we get:
Molar mass of carbon dioxide = 44 g/mol
Moles of carbon dioxide = 0.143 moles
Putting values in equation 1, we get:
To calculate the experimental yield of carbon dioxide, we use the equation:
Percentage yield of carbon dioxide = 90 %
Theoretical yield of carbon dioxide = 6.292 g
Putting values in above equation, we get:
Hence, the amount of carbon dioxide formed in the reaction is 5.663 grams
Answer: 0.74 moles
Explanation:
The first step is to figure out the chemical formula for calcium phosphate. Since we know that calcium is a metal, this will be an ionic bond. Calcium is written as Ca and has a charge of +2. Phosphate is written as PO4 with a charge of -3. To come up with the subscripts for this formula, cross the charges. That means that you will get .
Next, calculate how many grams one molecule of calcium is. Calcium has an atomic weight of 40, and there are 3 molecules of calcium, so 40 x 3 = 120. Phosphorus has an atomic weight of 31, and there are 2 molecules of phosphorus, so 31 x 2 = 62. Oxygen has an atomic weight of 16, and there are 8 molecules of oxygen, so 16 x 8 = 128. Adding all of those together gives you 310 g.
Now, using stoichiometry, we can figure out the question. We know that there are 230 grams. We also know that one mole weighs 310 g. If you divide 230 by 310, you will get your answer, which is 0.74 moles.