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Inessa [10]
3 years ago
6

If you try to place the compound on the pan over the flame, what could possibly happen? Explain your answer. [2 marks] anyone pl

ease help me!!:(​
Chemistry
1 answer:
Scilla [17]3 years ago
8 0

Answer:

it will probably flame up or explode or maybe start boiling

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Why would the volume of one object calculated using “Measurement and Calculation” differ from the volume of the same object calc
Mars2501 [29]

Answer:

Measuring the Volume of Solids

Rectangular prism - Multiply the measurement of the length times the width, then times the height.

Cube - Since all sides are the same measurement, it would be the measurement of any side, or edge, cubed, or a³

Explanation:

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3 years ago
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How many valence electrons does an atom of rubidium (Rb atomic number 37) have? A.One B.Five C.Six D.37
nadezda [96]
Electronic configuration of Rb: 2.8.8.8.8.3
Valence electron is 3....
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Please answer!
evablogger [386]
1.) A compound is a substance that originates from two or more separate elements. It shares some similarities with a mixture.

2.) A compound has quite different properties from which it was formed. It also cannot be separated easily. Compounds are formed by chemical reactions.

3.) A pure substance has a constant composition and has consistent properties. It can be a compound or an element, but its composition is constant.

Hope this helps. :)
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3 years ago
When a cold front is approaching, what happens?
Marta_Voda [28]

Answer:There is colder and drier air coming

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3 years ago
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A 1.67-g sample of solid silver reacted in excess chlorine gas to give a2.21-g sample of pure solid Agcl.The heat given off in t
kotegsom [21]

<u>Given:</u>

Mass of Ag = 1.67 g

Mass of Cl = 2.21 g

Heat evolved = 1.96 kJ

<u>To determine:</u>

The enthalpy of formation of AgCl(s)

<u>Explanation:</u>

The reaction is:

2Ag(s) + Cl2(g) → 2AgCl(s)

Calculate the moles of Ag and Cl from the given masses

Atomic mass of Ag = 108 g/mol

# moles of Ag = 1.67/108 = 0.0155 moles

Atomic mass of Cl = 35 g/mol

# moles of Cl = 2.21/35 = 0.0631 moles

Since moles of Ag << moles of Cl, silver is the limiting reagent.

Based on reaction stoichiometry: # moles of AgCl formed = 0.0155 moles

Enthalpy of formation of AgCl = 1.96 kJ/0.0155 moles = 126.5 kJ/mol

Ans: Formation enthalpy = 126.5 kJ/mol


6 0
3 years ago
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