Answer:
The bird appears farther
Explanation:
This is because as the light from the bird travels into the water which has a higher refractive index than air, light rays from the kingfisher bird bend towards the normal at the water surface and thus enter the eye of the scuba diver. Now, if we project the light rays from the eyes of the scuba diver into the air, we see that they appear to come from a point farther than that of the actual kingfisher bird perched on the branch.
<u>So, the bird appears to the diver to be farther from the surface than the actual bird</u>
Answer:
The distance that you marginally able to discern that there are two headlights rather than a single light source is 6.084 km
Explanation:
Given:
d = distance = 0.679 m
λ = wavelength of the light = 537 nm = 537x10⁻⁹m
dp = pupil diameter = 4.81 mm = 0.00481 m
Question: What distance, in kilometers, are you marginally able to discern that there are two headlights rather than a single light source, dx = ?
For the separation of the peak from the central maximum it is:

In this case, the two small sources of the headlights have the same angle as the images that form inside the eye

Answer:

Explanation:
Let at any moment of time the friend's car is at some horizontal distance "x" from the position of balloon.
Now if the altitude of the balloon is fixed and it is at height "h"
so here we will have

now we know that
initially the angle of the friend's car is 35 degree
so the horizontal distance will be

similarly if the angle after passing the car position is 36 degree
then we have

now the speed of the balloon is constant
so we have




so the final position of friend when the angle is 36 degree


Ok you need a punnett square? its gonna be easy, create the square first, Then put the letters in their, When done message me
Answer: 90m
Explanation:
Use Equation for distance:
S=a*t²/2
use eqation for acceleraton a=(Vf-Vs)/t
Vs- starting speed
Vf - final speed
a-accelaration
---------------------------------
a=5m/s²
Vs=0m/s
Vf=30m/s
use
a=(Vf-Vs)/t
to find time
t=(Vf-Vs)/a
t=30m/s/5m/s²
t=6s
Now calculate distance that object travel using:
S=(a*t²)72
s=(5m/s²*(6s)²)/2
S=90m