Answer:
The required angular speed ω of an ultra-centrifuge is:
ω = 18074 rad/sec
Explanation:
Given that:
Radius = r = 1.8 cm
Acceleration due to g = a = 6.0 x 10⁵ g
Sol:
We know that
Angular Acceleration = Angular Radius x Speed²
a = r x ω ²
Putting the values
6 x 10⁵ g = 1.8 cm x ω ²
Converting 1.8 cm to 0.018 m, also g = 9.8 ms⁻²
6 x 10⁵ x 9.8 = 0.018 x ω ²
ω ² = (6 x 10⁵ x 9.8) / 0.018
ω ² = 5880000 / 0.018
ω ² = 326666667
ω = 18074 rad/sec
The answer here is <span>The government is expansive</span>
Answer:
P = 23.32 W
Explanation:
In series
equivalent Resistance
R(eq)=R+R=2R
In parallel equivalent resistance
R(eq) = R*R/(R+R) =R/2
since.
power
P=V² / R
in series
⇒V = √(P*R)
=√(5.83*2R
)
=√(11.66R)
in parallel
P = V² / R(eq)
=(√(11.66R)²) / (R/2)
P=11.66 * R * 2/R
P = 23.32 W
Answer:
Explanation:
Momentum change:
: vector
p=mv
: the ball move downward with an angle theta to the vertical
:the ball move upward with the same angle theta to the vertical, with same speed
So: