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GaryK [48]
2 years ago
13

Can anyone please help me with this

Mathematics
1 answer:
Genrish500 [490]2 years ago
5 0

Answer:  I’m not very smart you don’t want my help

Step-by-step explanation:

You might be interested in
459 divided by 3 how to show your work on paper
melomori [17]
Bus stop method. 3 goes into 4 once. Remainer 1. Add that to the 5. Makes 15. 3 into 15 goes 5 times. No remainder. 3 goes into 9, 3 times and no remainer. So 459/3 is 153

7 0
2 years ago
Amino Buys A Book For Rupees 275 And Sells It At A Loss Of 15% How Much Does She Sell It For
Kruka [31]

Answer:

$233.75

Step-by-step explanation:

2.75 x 15 = 41.25

275 - 41.25 = $233.75

7 0
2 years ago
Read 2 more answers
A. Find the reflection of the point (-3, 2) about the origin.
nadezda [96]

Answer:

a. (3,-2)

b. (-5,-3)

5 0
3 years ago
Do you agree with the statement that " cubic functions must have at least 1 x-intercept but not more than 3, whereas quadratic f
vladimir2022 [97]

Answer:

Yes, I agree

Step-by-step explanation:

For the cubic function

A cubic function is represented as:

f(x)=ax^3+bx^2+cx+d

A cubic function may have 1, 2 or 3 x intercepts. This is shown below

For 3 x intercepts

y = x^3 - x

Equate y to 0

x^3 - x = 0

Expand

x(x^2 - 1) = 0

Express x^2 - 1 as difference of two squares

x(x - 1)(x +1 ) = 0

<em>x = 0 or 1 or -1</em>

For 2 x intercepts

y = x^3 - x

y  =(x-5)^2)(x+7)

Equate y to 0

(x-5)^2(x+7) = 0

Expand

(x-5)(x-5)(x+7) = 0

<em>x= 5 or x = -7</em>

For 1 x intercept

y = x^3

Equate y to 0

x^3 = 0

Take cube roots of both sides

x = 0

It has been shown above that a cubic function may have 1, 2 or 3.

So, I agree to the statement

For the quadratic function

A quadratic function will not have any x intercept when the function can not be factorized;

E.g.

y = x^2 + x + 17

<em>The above function has no x intercept.</em>

A quadratic function will have at least 1 x intercept when the function can be factorized;

E.g.

y = x^2- 6x + 9

Equate y to 0

x^2- 6x + 9 = 0

Expand

x^2 - 3x - 3x + 9 = 0

(x - 3)(x-3) = 0

x = 3

We've shown that a quadratic may have no x intercept, and it may also have x intercept(s)

Hence, I agree to both statement

3 0
2 years ago
Hi can someone help me with this
Ad libitum [116K]

Answer:

25 units

Step-by-step explanation:

Applying Pythagoras' Theorem,

(BD)^2= (CD)^2 + (BC)^2

(BC)^2= 65^2 - 60^2

(BC)^2= 625

BC= √625= 25

5 0
3 years ago
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