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grigory [225]
3 years ago
9

Which statements best describe science? Check all that apply.

Chemistry
2 answers:
Marat540 [252]3 years ago
5 0

Answer:

D,C, and A

Explanation:

VARVARA [1.3K]3 years ago
4 0

Answer:

Maybe B, try that Im sorry if I'm wrong

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What is the noble gas electron configuration of bismuth (Bi)? A. [Kr] 6s2 6p3 B. [Xe] 6s2 6p3 C. [Xe] 4f14 5d10 6s2 6p3 D. [Kr]
OlgaM077 [116]

The answer is C) Xe 4f14 5d10 6s2 6p3

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3 years ago
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A compound of uranium and fluorine is used to generate uranium for nuclear power plants. The gas can be decomposed to yield 2.09
Artemon [7]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

The gas can be decomposed to yield 2.09 parts by mass of uranium for every 1 part by mass of fluorine.If the relative mass of a uranium atom is 238 and the relative mass of a fluorine atom is 19, <span> the number of fluorine atoms that are combined with one uranium atom. is 6</span>

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3 years ago
What’s a conjugative Bas of OH-
LiRa [457]

Answer:

the answer is O²- hopefully

8 0
2 years ago
Liquid octane CH3CH26CH3 will react with gaseous oxygen O2 to produce gaseous carbon dioxide CO2 and gaseous water H2O . Suppose
Slav-nsk [51]

Answer:

The minimum mass of octane that could be left over is 43.0 grams

Explanation:

Step 1: Data given

Mass of octane = 73.0 grams

Mass of oxygen = 105.0 grams

Molar mass octane = 114.23 g/mol

Molar mass oxygen = 32.0 g/mol

Step 2: The balanced equation

2C8H18 + 25O2 → 16CO2 + 18H2O

Step 3: Calculate the number of moles

Moles = mass / molar mass

Moles octane = 73.0 grams / 114.23 g/mol

Moles octane = 0.639 moles

Moles O2 = 105.0 grams / 32.0 g/mol

Moles O2 = 3.28 moles

Step 4: Calculate the limiting reactant

For 2 moles octane we need 25 moles O2 to produce 16 moles CO2 and 18 moles H2O

O2 is the limiting reactant. It will completely be consumed. (3.28 moles). There will react 3.28 / 12.5 = 0.2624 moles. There will remain 0.639 - 0.2624  = 0.3766 moles octane

Step 5: Calculate mass octane remaining

Mass octane = moles * molar mass

Mass octane = 0.3766 moles * 114.23 g/mol

Mass octane = 43.0 grams

The minimum mass of octane that could be left over is 43.0 grams

3 0
3 years ago
Only _____ live part of their lives like fish and the rest of their lives as land animals.
dedylja [7]

Answer:

amphibians

Explanation:

because frogs have to stay in water while tadpole then they come to land

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2 years ago
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