¡Hellow!
For this problem, first, lets convert the seconds in hours:
5,4x10³
5400
h = sec / 3600
h = 5400 s / 3600
h = 1,5
Let's recabe information:
d (Distance) = 386 km
t (Time) = 1,5 h
v (Velocity) = ?
For calculate velocity, let's applicate formula:
![\boxed{\boxed{\textbf{d = v * t} } }](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cboxed%7B%5Ctextbf%7Bd%20%3D%20v%20%2A%20t%7D%20%7D%20%7D)
Reeplace according we information:
386 km = v * 1,5 h
v = 386 km / 1,5 h
v = 257,33 km/h
The velocity of the train is of <u>257,33 kilometers for hour.</u>
<u></u>
Extra:
For convert km/h to m/s, we divide the velocity of km/h for 3,6:
m/s = km/h / 3,6
Let's reeplace:
m/s = 257,33 km/h / 3,6
m/s = 71,48
¿Good Luck?
Vertical line from the centre of mass is inside the base of the tower.
Answer:
According to Newton's Second Law of Motion :
Where,
F = Force Applied
m = Mass of the object
a = Acceleration
Now, we will use this law to solve this question.
Given :
Acceleration or a = 15.3 m/s²
Force = 44 N
Mass = ?
Substitute, the given values in the formula.
F = ma
⇒ m = F/a
m = 44/15.3
<u>m = 2.9 kg</u>
Answer: 0.56 m/s
Explanation:
hello, there is 25° inclination angle for the chute in the drawing. Thankfully, I know this problem. The conservation of momentum.
so there are X and Y components for the momentum in this problem. The Y component is not conserved as when the coal gets in the cart, the normal force exerted by the surface reduces it to 0.
Now, the X component is definitely conserved here.
so you have the momentum of the cart which is 440*0.5 added to the momentum of the chunk which is 150*0.8*cos(25°), that is the momentum before the coupling between the objects. Afterwards both objects will have the same velocity, so we write the equation like this:
![440*0.5 + 150*0.8*cos(25) = 440*v_{final} + 150*v_{final} \\ => 220+120*cos(25) = (440+150)v_{final} => v_{final} = \frac{220+120*cos(25)}{590} = 0.56 m/s](https://tex.z-dn.net/?f=440%2A0.5%20%2B%20150%2A0.8%2Acos%2825%29%20%3D%20440%2Av_%7Bfinal%7D%20%2B%20150%2Av_%7Bfinal%7D%20%5C%5C%20%3D%3E%20220%2B120%2Acos%2825%29%20%3D%20%28440%2B150%29v_%7Bfinal%7D%20%3D%3E%20v_%7Bfinal%7D%20%3D%20%5Cfrac%7B220%2B120%2Acos%2825%29%7D%7B590%7D%20%20%3D%200.56%20m%2Fs)