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ANTONII [103]
3 years ago
9

What is the radius of the circle with this equation of (x-5)^2 + 4+7)^2 = 8?

Mathematics
1 answer:
Leya [2.2K]3 years ago
4 0

Answer:

2\sqrt{2} is the exact answer

2.83 is the answer to the nearest 100th

Step-by-step explanation:

I think the equation should be

(x-5)^2 + (y+7)^2 = 8 instead of (x-5)^2 + 4+7)^2 = 8

r^{2} = 8

r = \sqrt{8} = 2\sqrt{2}

2\sqrt{2} is the exact answer

2.83 is the answer to the nearest 100th

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Given:

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f(x)=350(1-0.12)^x

To find:

The initial value of the function.

Solution:

We have,

f(x)=350(1-0.12)^x

The value of the function at x=0 is called the initial value of the function.

For x=0, we get

f(0)=350(1-0.12)^0

f(0)=350(0.88)^0

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f(0)=350(1)

f(0)=350

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