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2 years ago

Ozone, O3 methane, CH4 oxygen gas, O2 Are classified as

Physics

2 answers:

ratelena [41]2 years ago

7 0

They are all gasses at room temperature.

erma4kov [3.2K]2 years ago

5 0

I would think compounds.

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The energy band gap of GaAs is 1.4 eV. Calculate the optimum wavelength of light for

notsponge [240]

Answer:

The optimum wavelength = (8.863 × 10⁻⁷) m = 886.3 nm

Explanation:

The light that will generate the photovoltaic energy of 1.4 eV will must have that amount of energy

Energy of light waves is given as

E = hf

h = Planck's constant = (6.626 × 10⁻³⁴) J.s

f = Frequency of the light

The frequency is then further given as

f = (c/λ)

c = speed of light = (3.0 × 10⁸) m/s

λ = wavelength of the light = ?

E = (hc/λ)

λ = (hc/E)

Energy = E = 1.4 eV = 1.4 × 1.602 × 10⁻¹⁹ = (2.2428 × 10⁻¹⁹) J

λ = (6.626 × 10⁻³⁴ × 3.0 × 10⁸)/(2.2428 × 10⁻¹⁹)

λ = (8.863 × 10⁻⁷) m = 886 nm

Hope this Helps!!!

3 0

2 years ago

Determine the largest intensity w of the uniform loading that can be applied to the frame without causing either the average nor

jeka94

.........................|||||||..............................

8 0

2 years ago

I don't know the answer but I think that it is yes I just don't want to get it wrong

mrs_skeptik [129]

Yes your answer should be true.

8 0

2 years ago

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Six artificial satellites circle a space station at constant speed. The mass m of each satellite, distance L from the space stat

nikklg [1K]

Answers:

a) $T_{2}>T_{5}>T_{1}>T_{3}=T_{6}>T_{4}$

b) $a_{4}>a_{6}>a_{1}>a_{3}>a_{5}>a_{2}$

Explanation:

a) Since we are told the satellites circle the space station at constant speed, we can assume they follow a uniform circular motion and their tangential speeds $V$ are given by:

$V=\omega L=\frac{2\pi}{T} L$ (1)

Where:

$\omega$ is the angular frequency

$L$ is the radius of the orbit of each satellite

$T$ is the period of the orbit of each satellite

Isolating $T$ :

$T=\frac{2 \pi L}{V}$ (2)

Applying this equation to each satellite:

$T_{1}=\frac{2 \pi L}{V_{1}}=261.79 s$ (3)

$T_{2}=\frac{2 \pi L}{V_{2}}=1570.79 s$ (4)

$T_{3}=\frac{2 \pi L}{V_{3}}=196.349 s$ (5)

$T_{4}=\frac{2 \pi L}{V_{4}}=98.174 s$ (6)

$T_{5}=\frac{2 \pi L}{V_{5}}=785.398 s$ (7)

$T_{6}=\frac{2 \pi L}{V_{6}}=196.349 s$ (8)

Ordering this periods from largest to smallest:

$T_{2}>T_{5}>T_{1}>T_{3}=T_{6}>T_{4}$

b) Acceleration $a$ is defined as the variation of velocity in time:

$a=\frac{V}{T}$ (9)

Applying this equation to each satellite:

$a_{1}=\frac{V_{1}}{T_{1}}=0.458 m/s^{2}$ (10)

$a_{2}=\frac{V_{2}}{T_{2}}=0.0254 m/s^{2}$ (11)

$a_{3}=\frac{V_{3}}{T_{3}}=0.4074 m/s^{2}$ (12)

$a_{4}=\frac{V_{4}}{T_{4}}=1.629 m/s^{2}$ (13)

$a_{5}=\frac{V_{5}}{T_{5}}=0.101 m/s^{2}$ (14)

$a_{6}=\frac{V_{6}}{T_{6}}=0.814 m/s^{2}$ (15)

Ordering this acceerations from largest to smallest:

$a_{4}>a_{6}>a_{1}>a_{3}>a_{5}>a_{2}$

4 0

2 years ago

Through the process of blank

maksim [4K]

Answer:

Subduction, Trench, Mantle

Explanation:

8 0

2 years ago

Read 2 more answers