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Yakvenalex [24]
3 years ago
7

Ozone, O3 methane, CH4 oxygen gas, O2 Are classified as

Physics
2 answers:
ratelena [41]3 years ago
7 0
They are all gasses at room temperature.
erma4kov [3.2K]3 years ago
5 0
I would think compounds.
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Which has greater
Taya2010 [7]
The at the top, the higher something is the more potential energy it has because if both fall the one at the top will have more kinetic energy
5 0
3 years ago
The turbines can be seen inside this hydroelectric dam. Why are they located at that particular height?
Yakvenalex [24]

Answer:

3

Explanation:

the answer is number three

5 0
4 years ago
Read 2 more answers
Sort the items based on whether they are simple machines or compound machines.
Tom [10]

Answer:

Simple machine: pair of tongs, seesaw and wheelbarrow

Compound machine: sewing machine, fishing rod and reel and crane.

Explanation:

Simple machine is the simplest device to use mechanical advantages. It has simplest mechanism to multiply the magnitude of force.

So, pair of tongs, seesaw and wheelbarrow are the example of simple machine because their mechanism is simplest.

Compound machine is a device that is made up of more than one simple machine.

so, sewing machine, fishing rod and reel and crane are example of compound machine because these devices shows more than one machine in it.

Thus, classification is as follows:

Simple machine: pair of tongs, seesaw and wheelbarrow

Compound machine: sewing machine, fishing rod and reel and crane.

3 0
4 years ago
Read 2 more answers
How long does a player sit out of a game of handball for committing a second or third foul?
yulyashka [42]

Answer:

Walking’ - If a handball player takes more than three steps without dribbling (bouncing the ball) or holds the ball for more than 3 seconds without bouncing it, shooting or passing, then that is deemed ‘walking' and possession is lost.

'Double dribble’ - Handball players cannot receive the ball and bounce it, then hold the ball, and bounce it again. This is termed ‘double dribble’ and is against the rules.

Askmeanything2♡

5 0
3 years ago
On an asteroid, the density of dust particles at a height of 3 cm is ~30% of its value just above the surface of the asteroid. A
Anvisha [2.4K]

From the law of atmosphere

N_v(y) = n_0*e^{-\frac{mgy}{Kb*T}}

Where

n_0 = constant and is number density where the height y = 0cm

n_V = Number density at height y=3cm

Kb = Boltzmann constant = 1.38*10^{-23}J/K

T=20K

m = 10^{-19}kg

Re-arranging the equation to have the value of the gravity,

\frac{N_v(y)}{n_0} = e^{-\frac{mghy}{KbT}}

ln(\frac{N_v(y)}{n_0}) = -\frac{mgy}{KbT}

Since it is 30% of value above surface, therefore N_v = 0.3n_0

ln(\frac{0.3n_0}{n_0}) = -\frac{mgy}{KbT}

g = -\frac{KbT ln(0.3)}{my}

g = -\frac{(1.38*10^{-23}J/K)(20K)(Ln(0.3))}{10^{-19}(3*10^{-2})}

g = \frac{1.38*2*ln(0.3)*10^{-22}}{3*10^{-4}}

g = 1.104*10^{-1}m/s^2

g = 0.1m/s^2

Therefore the correct answer is C.

4 0
4 years ago
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