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Yakvenalex [24]
3 years ago
7

Ozone, O3 methane, CH4 oxygen gas, O2 Are classified as

Physics
2 answers:
ratelena [41]3 years ago
7 0
They are all gasses at room temperature.
erma4kov [3.2K]3 years ago
5 0
I would think compounds.
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A small glass bead has been charged to +20 nC. A small metal ball bearing 1.0 cm above the bead feels a 0.018 N downward electri
Alla [95]

Answer:

q=1\times10^{-8}C

Explanation:

Let the charge on the ball bearing is q.

charge on glass bead, Q = 20 nC = 20 x 10^-9 C

Force between them, F = 0.018 N

Distance between them, d = 1 cm = 0.01 m

By use of Coulomb's law in electrostatics

F=\frac{KQq}{d^{2}}

By substituting the values

0.018=\frac{9\times10^{9}\times20\times10^{-9}q}{0.01^{2}}

q=1\times10^{-8}C

Thus, the charge on the ball bearing is q=1\times10^{-8}C

7 0
3 years ago
What causes objects to move or stay still (support your details with claims and evidence)
maxonik [38]
Force moves the object but if the same anyone force is applied to both sides then it doesn’t move
6 0
3 years ago
Given a force of 100 N and acceleration of 5 m/s2, what is the mass
tatyana61 [14]

Answer:

20 kg

Explanation:

remember the equation f=ma.

100 N=force

5 m/s2= acceleration

so you need to divide force by acceleration: 100 N/ 5 m/s2= 20 kg, to get the mass.

8 0
2 years ago
What force is required to accelerate a body with a mass of 15kilograms at a rate of
Paladinen [302]

The force required is

                     (15 kg) x (the acceleration, in m/s²)          newtons.

4 0
3 years ago
When you drink cold water, your body must expend metabolic energy in order to maintain normal body temperature (37° C) by warmi
Gelneren [198K]

Answer:

7.72 Liters

Explanation:

normal body temperature = T_body =37° C

temperature of ice water = T_ice =0°c

specfic heat of water = c_{water} =4186J/kg.°C

if the person drink 1 liter of cold water mass of water is = m = 1.0kg

heat lost by body is Qwater =mc_{water} ΔT

                                           = mc{water} ( T_ice - T_body)

                                             = 1.0×4186× (0 -37)

                                             = -154.882 ×10^3 J

here negative sign indicates the energy lost by body in metabolic process energy expended due to brisk - hour long walk is Q_{walk} = 286 kilocalories

            = 286×4186J

so number of liters of ice water have to drink is

n×Q_{water} =Q_{walk}                                                                        n= Q_{walk}/ Q_{water}

= 286×4186J/154.882×10^3 J

 = 7.72 Liters

7 0
3 years ago
Read 2 more answers
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