Answer:
9,000 N.
Explanation:
Workdone can be defined as the ability to do work. It is also the product of the force and the distance it is being moved.
Mathematically,
W = F * d
= 180,000/2
= 90,000 N.
Weight of the 10 cars = 90,000 N.
Weight of a car = 90000/10
= 9,000N.
Answer:
Explanation:
The force of friction between the quails feet and the ground is:
So the coefficient of static is solve
Answer:
Work done = force x displacement
= 500 x 20
= 10000 J
Hope this helps!
Radial acceleration is = v^2/r
Therefore (8.8m/s)^2/(25m)= 3.10m/s^2
Hope this helps you! Any questions please just ask! Thank you!
Answer:
892 Hz or 842 Hz
Explanation:
Given
The frequency of first guitar is 867 Hz
Beat is produced for every 0·04 s
∴ Beat has a time period of 0·04 s
<h3>Beat frequency is defined as the inverse of the time period of the beat </h3>
Beat frequency = 1 ÷ (Time period) = 1 ÷ 0·04 = 25 Hz
Let the frequency of the second guitar be f Hz
<h3>Beat frequency is defined as the absolute difference between the two frequencies</h3>
∴ Beat frequency = (867 - f) or (f - 867)
First case
25 = 867 - f ⇒ f = 842 Hz
Second case
25 = f - 867 ⇒ f = 892 Hz
∴ Possible frequencies of second guitar could be 892 Hz or 842 Hz