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3 years ago

What are the cons of using a cup made of ceramic

2 answers:

6 0

The cons of using a cup made of ceramic are that it can crack when a heavy item hits it, is weak, size inaccuracy can be difficult to control when processing and drinks can taste slightly odd in particular.

Olenka [21]3 years ago

6 0

<span>
disadvantages using a cup made of ceramic: </span><span>Poor shock resistance, it can crack when knocked with heavy items, and it's weak in tension, cannot be recycled, and has an odd taste. </span>

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An object is located 70 cm from a concave mirror with a focal length of 15 cm. What is the image

Stels [109]

(a) The distance of the image formed by the concave mirror is 19.1 cm.

(b) The image formed is diminished and real.

<h3>Image distance </h3>

The distance of the image formed by the concave mirror is calculated as follows;

1/f = 1/v + 1/u

1/v = 1/f - 1/u

1/v = 1/15 - 1/70

1/v = 0.05238

v = 1/0.05238

v = 19.1 cm

The image distance is smaller than object distance, thus the image formed is diminished and real.

Learn more about concave mirror here: brainly.com/question/13164847

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5 0

1 year ago

3. Which planet, other than Earth, is confirmed to have water on it?

Nadusha1986 [10]

Mars.

Water exists as small amounts of ice on Mars and as water vapor. It is suspected that Mars used to have flowing water on it, but that there is none left now.

8 0

2 years ago

Before Freddy lands on the skateboard it has a certain momentum. After landing, the skateboards momentum

Nadya [2.5K]

Answer:

remains the same

Explanation:

Momentum refers to the quantity of motion of a body. When any body of mass moves, it possess momentum. Numerically,

Momentum = mass x velocity

i.e. momentum is the product of the mass x velocity

Momentum of a body is always conserved.

In the context, the skateboard has certain momentum before Freddy lands on it. After Freddy lands, the momentum of skateboard remains the same, there is no change in the momentum.

This is because, here the momentum is conserved. After Freddy lands on the skateboard, the total mass on the skateboard increases and so the velocity decreases making the momentum same before the landing.

3 0

2 years ago

Two cylindrical rods, one copper and the other iron, are identical in lengths and cross-sectional areas. They are joined, end to

Pie

Answer:

Vc = 2.41 v

Explanation:

voltage (v) = 16 v

find the voltage between the ends of the copper rods .

applying the voltage divider theorem

Vc = V x ( $\frac{Rc}{Rc + Ri}$ )

where

Rc = resistance of copper = $\frac{ρl}{a}$ (l = length , a = area, ρ = resistivity of copper)

Ri = resistance of iron = $\frac{ρ₀l}{a}$ (l = length , a = area, ρ₀ = resistivity of copper)

Vc = V x ( $\frac{\frac{ρl}{a}}{\frac{ρl}{a} + \frac{ρ₀l}{a}}$ )

Vc = V x ( $\frac{ρ x (\frac{l}{a})}{(ρ + ρ₀) x (\frac{l}{a})}$ )

Vc = V x ( $\frac{ρ}{ρ + ρ₀}$ )

where

ρ = resistivity of copper = 1.72 x 10^{-8} ohm.meter

ρ₀ = resistivity of iron = 9.71 x 10^{-8} ohm.meter

Vc = 16 x ( $\frac{1.72 x 10^{-8}}{1.72 x 10^{-8} + 9.71 x 10^{-8}}$ )

Vc = 2.41 v

5 0

3 years ago

Two identical asteroids travel side by side while touching one another. If the asteroids are composed of homogeneous pure iron a

victus00 [196]

Answer:

diameter = 21.81 ft

Explanation:

The gravitational force equation is:

$F=\frac{GMm}{R^{2} }$

Where:

F => Gravitational force or force of attraction between two masses
M => Mass of asteroid 1
m => Mass of asteroid 2
R => Distance between asteroids 1 and 2 (from center of gravity)

We also know that the asteroids are identical so their masses are identical:

Since R is the distance between centers of the two asteroids and their diameters are identical (see attachment), we can conclude that:

R=d=2r

We don´t know the mass of the asteroids but we know they are composed of pure iron, so we can relate their masses to their density:

m=ρV

This is going to be helpful because the volume of a sphere is:

$\frac{4}{3}\pi r^{3}$

And know we can write our original force of gravity equation in terms of the radius of the asteroids:

$F=\frac{GMm}{R^{2} } =\frac{Gmm}{(2r)^{2} } =\frac{Gm^{2} }{4r^{2} }$
$F=\frac{G ( \frac{4}{3}\pi r^{3}ρ)^{2} }{4r^{2} }$
$F= \frac{G(16)\pi ^{2} r^{6} ρ^{2}}{(9)(4)r^{2} } =\frac{G(16)\pi ^{2} r^{4}ρ^{2} }{36}$