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Andreyy89
3 years ago
15

What are the cons of using a cup made of ceramic

Physics
2 answers:
Alex777 [14]3 years ago
6 0
The cons of using a cup made of ceramic are that it can crack when a heavy item hits it, is weak, size inaccuracy can be difficult to control when processing and drinks can taste slightly odd in particular. 
Olenka [21]3 years ago
6 0
<span>
disadvantages using a cup made of ceramic: </span><span>Poor shock resistance, it can crack when knocked with heavy items, and it's weak in tension, cannot be recycled, and has an odd taste. </span>
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An ___________ is a current-carrying wire wrapped around an iron core.
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A pin-supported, vertically-oriented 1-m long thin rod is struck by a pellet at m down from the pin at the top. The mass of the
Natasha_Volkova [10]

Answer:

the angular velocity of the rod immediately after being struck by the pellet, provided that the pellet gets lodged in the rod is = 0.5036 k` rad/s

Explanation:

Using the conservation of momentum of approach.

From the question; the pellet is hitting at a distance of 0.4 m down from the point of rotation of the rod.

So, the angular momentum of the system just before the collision occurs  with respect to the axis of the rotation is expressed by the formula:

L_i ^ { ^  \to } = mp ( r_y } ^ { ^  \to }  * v_{pi}  ^ { ^  \to } )    ----- equation (1)

The position vector can now be :

x ^ { ^  \to } = - 0.4 \ j \ m

Also, given that :

v_{p,i}  ^ { ^  \to } = (280 \ i - 350 \  j)  \ m/s

Replacing the value into above equation (1); we have:

L_i ^ { ^  \to } =0.012 ((- \ 0.4 \  j) *(280 \ i - 350 \ j ))

L_i ^ { ^  \to } =0.012 * 112 \  k    (by using cross product )

L_i ^ { ^  \to } = 1.344 k` \  \  kg  m^2 s^{-1}

However; the moment of inertia of the rod about the axis of rotation is :

I_{rod} = \frac{1}{3}m_rl^2  \\ \\ I_{rod} = \frac{1}{3}*8*1^2 \\ \\ I_{rod} = \frac{8}{3} \ \  kg  \ m^2

Also, the moment of inertia of the pellet about the axis of rotation is:

I_{pellet} = m_pr_y^2 \\ \\ I_{pellet} = 0.012 *0.4^2  \\ \\ I_{pellet} = 1.92*10^{-3} kg . m^2

So, the moment of inertia of the rod +pellet system is:

I = I_{rod}+I_{pellet}

I =( \frac{8}{3}+1.92 *10^{-3} )kg. m^2

I = 2.6686 \  kg. m^2

The final angular momentum is :

L_f ^ {^ \to}  = I \omega { ^ {^ \to} } = 2.6686 \  \omega  ^ {^ \to}

The angular velocity of the rod \omega is determined by equating the angular momentum just before the collision with the final angular momentum (i.e after the collision).

So;

L_f ^ {^ \to} = L_i ^ { ^ \to}

2.6686 \omega ^ {^ \to} = 1.344 \ k ^ {^ \to}

\omega  ^ {^ \to} = \frac{1.344 \ k`}{2.6686}

= 0.5036 k` rad/s

Hence; the angular velocity of the rod immediately after being struck by the pellet, provided that the pellet gets lodged in the rod is = 0.5036 k` rad/s

7 0
3 years ago
Which best describes the result when the concentration of a solution is increased? The amount of solute is increased, and the co
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The amount of solute is increased, and the conductivity of the solution is increased

Explanation:

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Learn More

Conductivity of a solution :brainly.com/question/9486572

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________________________can turn igneous rock into sediment
siniylev [52]
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A batter hits a pitched ball when the center of the ball is 1.22 m above the ground. The ball leaves the bat at an angle of 45°
Sveta_85 [38]

Answer:

2.56m

Explanation:

This is problem 4.47 from your textbook.

Find: Whether a batted baseball clears a fence, and by what amount it does or does not.

Given: The baseball’s initial launch height and angle, the range the baseball would have without the fence, the distance to the fence and its height.

Let the y axis run vertically and the x axis horizontally. Let the range the baseball would have without the fence be R=107 m, with the distance to the fence d=97.5m and its height hfence=7.32 m. The baseball is batted at an angle θ=45° at speed vi a height of hbat=1.22m above the ground.

Let the origin be at the position the ball leaves the bat. The height of the fence relative to the height of the bat is then

δh = hfence − hbat

What we really need to determine is the ball’s y coordinate at x = d. If y > δh, the ball clears the fence. We can use the range the baseball would have without the fence and the launch angle to find the ball’s speed, which will allow a complete calculation of the trajectory.

Relevant equations: We need only the equations for the range and trajectory of a projectile over level ground:

R = (vi*sin2θ)/g

For convenience sake and easy reading, I extracted the solution of your textbook for the remaining parts of the solution.

Hence, it is seen that the ball does clear the fence, by approximately 2.56 m

7 0
3 years ago
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