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3 years ago

Which of the following describes an organ system?

Physics

2 answers:

poizon [28]3 years ago

7 0

A group of organs working together.

Anna007 [38]3 years ago

5 0

A group of organs working together

You might be interested in

See the person on the right side of the front car. Six reference points could be used to show that the person is in / is NOT in

Rasek [7]

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

1. According to person standing on ground ~

The person is in motion

2. According to The car ~

The person is not in motion

3. According to the Seat ~

The person is not in motion

4. According to another person on ride ~

The person is not in motion

5. According to the track ~

The person is in motion

6. According to the Sun ~

The person is in motion

I hope that's what you were looking for, goodluck for your assignment ~

7 0

2 years ago

Visible light waves do not diffract as well as radio waves because

Anvisha [2.4K]

they have more energy than radio waves.

because the wavelength of the light waves are too small

3 0

3 years ago

Consider a model of a hydrogen atom in which an electron is in a circular orbit of radius r = 5.92×10−11 m around a stationary p

DaniilM [7]

Answer:

2.068 x 10^6 m / s

Explanation:

radius, r = 5.92 x 10^-11 m

mass of electron, m = 9.1 x 10^-31 kg

charge of electron, q = 1.6 x 10^-19 C

As the electron is revolving in a circular path, it experiences a centripetal force which is balanced by the electrostatic force between the electron and the nucleus.

centripetal force = $\frac{mv^{2}}{r}$

Electrostatic force = $\frac{kq^{2}}{r^{2}}$

where, k be the Coulombic constant, k = 9 x 10^9 Nm^2 / C^2

So, balancing both the forces we get

$\frac{kq^{2}}{r^{2}}=\frac{mv^{2}}{r}$

$v=\sqrt{\frac{kq^{2}}{mr}}$

$v=\sqrt{\frac{9\times 10^{9}\times1.6\times 10^{-19}\times 1.6\times 10^{-19}}{9.1\times 10^{-31}\times 5.92\times10^{-11}}}$

v = 2.068 x 10^6 m / s

Thus, the speed of the electron is give by 2.068 x 10^6 m / s.

6 0

3 years ago

A(n) 2602 kg van runs into the back of a(n)

forsale [732]

Answer:

8.5 m/s

Explanation:

please see paper for the work!

8 0

3 years ago

Calculate the length of a simple pendulum that oscillates with a frequency of 0.4Hz g=10m/s2 , ^=3.142

earnstyle [38]

Answer:

Explanation:

For simple pendulum the formula is

$T=2\pi\sqrt{\frac{l}{g} }$

Where T is time period , l is length and g is acceleration due to gravity .

$\frac{1}{n} =2\pi\sqrt{\frac{l}{g} }$

n is frequency

Putting the values

$\frac{1}{.4} =2\pi\sqrt{\frac{l}{10} }$

$\frac{l}{10} = .1584$

l = 1.584 m

4 0

3 years ago