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Inga [223]
3 years ago
12

Reducing the CFM through the evaporator will cause the amount of moisture removed from the air to ____________________. A. stay

the same B. decrease C. increase
Engineering
1 answer:
vodomira [7]3 years ago
3 0

Answer:

C. increase

Explanation:

Pollution can be defined as the physical degradation or contamination of the environment through an emission of harmful, poisonous and toxic chemical substances.

On a related note, particulate pollution is a form of pollution that is responsible for the degradation of the environment.

Particulate matter is also referred to as particle pollution or atmospheric aerosol particles and it can be defined as a complex microscopic mixture of liquid droplets and solid particles that are suspended in air. Other forms of particle pollution includes space debris and marine debris. Some examples of particulate pollution are dusts, soot, dirt, smoke, etc.

Generally, when cubic feet-per-minute (CFM) are reduced through the use of an evaporator, it will cause the amount of moisture removed from the air to increase.

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Most business owners begin his business in order to increase profit and to expand.

<h3>What are Business Practices?</h3>

This refers to the various ways in which a business owner decides to organize his business and the policies which guides it.

With this in mind, we can see that Mr X believes that it is a good business practice to <em>prioritize the work</em> that seems the most difficult and the most likely to kill their projects but this is not a good business practice because it can put the entire business in jeopardy.

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If you are unsure about holding a piece of wood to be drilled, then you should always use a
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Even though the content of many alcohol blends doesn’t affect engine drive ability using gasoline with alcohol in warm weather m
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Even though the content of many alcohol blends doesn't affect engine driveability, using gasoline with alcohol in warm weather may cause: decrease in fuel economy.

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2 years ago
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3 years ago
Problem Statement: Air flows at a rate of 0.1 kg/s through a device as shown below. The pressure and temperature of the air at l
Tema [17]

Answer:

The answer is "+9.05 kw"

Explanation:

In the given question some information is missing which can be given in the following attachment.

The solution to this question can be defined as follows:

let assume that flow is from 1 to 2 then

Q= 1kw

m=0.1 kg/s

From the steady flow energy equation is:

m\{n_1+ \frac{v^2_1}{z}+ gz_1 \}+Q= m \{h_2+ \frac{v^2_2}{2}+ gz_2\}+w\\\\\ change \ energy\\\\0.1[1.005 \times 800]-1= 0.01[1.005\times 700]+w\\\\w= +9.05 \ kw\\\\

If the sign of the work performed is positive, it means the work is done on the surrounding so, that the expected direction of the flow is right.

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