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3 years ago

When you arrive at an intersection with a stop sign in your direction, if there is no marked stop

Engineering

2 answers:

kakasveta [241]3 years ago

6 0

Answer:

The answer is B. Wait for the pedestrians in the crosswalk to cross, then stop on the pedestrian crosswalk.

Illusion [34]3 years ago

3 0

Answer:

C: Stop before entering the pedestrian crosswalk.

Explanation:

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How deep does electrical conduit need to be buried?

GenaCL600 [577]

In general, bury metal conduits at least 6 inches below the soil surface. You may also run them at a depth of 4 inches under a 4-inch concrete slab. Under your driveway, the conduits must be below a depth of 18 inches, and under a public road or alleyway, they must be buried below 24 inches.

7 0

3 years ago

An ideal fluid flows through a pipe made of two sections with diameters of 1.0 and 3.0 inches, respectively. The speed of the fl

geniusboy [140]

Answer:

$(\frac{r_1}{r_2})^2=\frac{1}{9}$

Explanation:

From the question we are told that:

Diameter 1 $d_1=1.0$

Diameter 2 $d_2=3.0$

Generally the equation for Radius is mathematically given by

At Diameter 1

$r_{1}=\frac{1}{2} inch$

At Diameter 2

$r_{2}=\frac{3}{2} inch$

Generally the equation for continuity is mathematically given by

$A_1V_1=A_2V_2$

Therefore

$(\frac{r_1}{r_2})^2=(\frac{1/2}{3/2})^2$

$(\frac{r_1}{r_2})^2=\frac{1}{9}$

5 0

3 years ago

The car travels along the circular path such that its speed is increased by at = (0.5et ) m/s2 , where t is in seconds. Determin

Zolol [24]

Answer:

acceleration = 24.23 ms⁻¹

Explanation:

Let's gather the data:

The acceleration of the car is given by a = 0.5 $e^{t}$

The acceleration is the change in the speed in relation to time. In other words:

$\frac{dv}{dt}$ = a = a = 0.5 $e^{t}$ ...1

Solving the differential equation yields:

v = 0.5 $e^{t}$ + C₁

Initial conditions : 0 = 0.5 $e^{0}$ + C₁

C₁ = -5

at any time t, the velocity is: v= 0.5 $e^{t}$ - 5

Solving for distance, s = 0. 5 $e^{t}$ - 0.5 t - 0.5

18 = 0.5 $e^{t}$ - 0.5 t - 0.5

t = 3.71 s

Substitute t = 3.71 s

v= 0.5 $e^{t}$ - 5

= 19.85 m/s

a = 0.5 $e^{t}$ ...1

= 20.3531

an = $\frac{v^{2} }{p}$

= $\frac{(19.853)^{2} }{30}$

= 13.1382

Magnitude of acceleration = $\sqrt{ (a)^{2} + (an)^{2} }$

= $\sqrt{(20.3531)^{2} +(13.1382)^{2} }$

= 24.23 ms⁻¹ Ans

6 0

3 years ago

I really need help on this!

Dafna1 [17]

C: benchmark because I have done this before

8 0

3 years ago

Read 2 more answers

Which of the following best describes the mechanical energy of an object?

Flauer [41]

In other words, an object possesses mechanical energy when it has the ability to do work due to its position or motion. Mechanical energy can take the form of either kinetic energy, which is energy due to an object's motion, or potential energy, which is stored energy due to an object's position.

5 0

3 years ago