All categories

3 years ago

If you increase the pressure of a gas above the liquid, how does that affect the amount of gas dissolved in the liquid?

Chemistry

1 answer:

Reika [66]3 years ago

7 0

Answer:

The solubility of gases depends on the pressure: an increase in pressure increases solubility, whereas a decrease in pressure decreases solubility. This statement is basically Henry's Law, which states that the solubility of a gas in a liquid is directly proportional to the pressure of that gas above the surface of the solution. This can be expressed in the equation:

s=k×Pgas

where s is solubility in M

k is Henry's constant in M/atm

P is the vapor pressure of the gas over the solution

Another way of explaining this is that higher pressures lead to greater force in collisions between the gas particles above the solution and the solution itself. Their average kinetic energy is greater, and their average speeds are greater. So it is more likely that some of the particles will go into the solution and get dissolved.

You might be interested in

Chemical and physical properties of calcite

Semenov [28]

Answer:

Chemical Classification Carbonate

Explanation:

7 0

4 years ago

Choose all the answers that apply. Which of the following will decrease reaction rate? increase pressure decrease temperature in

zavuch27 [327]

The following quantities will effect the reaction rate as follows:

1. On increasing Concentration of the reactant: Rate of the reaction will increases.

2. On increasing pressure : Increases the rate of reaction to the side where there are fewer number of molecules.

3.On increasing temperature of an endothermic reaction: Increases the rate of reaction

4. On decreasing temperature of an endothermic reaction: Increases the rate of reaction.

So the answer is increase pressure, decrease temperature, increase concentration will increases the rate of the reaction.

6 0

3 years ago

Read 2 more answers

What are some examples of gases at room temperature

Lady_Fox [76]

Answer:

Nitrogen, Hydrogen, Oxygen, Chlorine, and Fluorine are all gases at room temperature.

Explanation:

6 0

3 years ago

Help me plz and need it bad

tatyana61 [14]

Answer:

Explanation: p + ci=pci

h+o=h io

4 0

3 years ago

At a particular temperature, K 3.39 for the reaction SO2(9) + NO2(9) SOs(9) +NO(9) If all four gases had initial concentrations

Korvikt [17]

Answer:

The equilibrium concentrations are:

[SO2]=[NO2] = 0.563 M

[SO3]=[NO] = 1.04 M

Explanation:

<u>Given:</u>

Equilibrium constant K = 3.39

[SO2] = [NO2] = [SO3] = [NO] = 0.800 M

<u>To determine:</u>

The equilibrium concentrations of the above gases

Calculation:

Set-up an ICE table for the given reaction

$SO2(g) + NO2(g)\rightleftharpoons SO3(g) + NO(g)$

I 0.800 0.800 0.800 0.800

C -x -x +x +x

E (0.800-x) (0.800-x) (0.800+x) (0.800+x)

The equilibrium constant is given as:

$Keq = \frac{[SO3][NO]}{[SO2][NO2]}=\frac{(0.800+x)^{2}}{(0.800-x)^{2}}$

$3.39=\frac{(0.800+x)^{2}}{(0.800-x)^{2}}$

x = 0.2368 M

[SO2]=[NO2] = 0.800 -x = 0.800 - 0.2368 = 0.5632 M

[SO3]=[NO] = 0.800 +x = 0.800 + 0.2368 = 1.037 M

4 0

3 years ago