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babunello [35]
3 years ago
10

Choose all the answers that apply. Which of the following will decrease reaction rate? increase pressure decrease temperature in

crease concentration decrease concentration
Chemistry
2 answers:
bazaltina [42]3 years ago
7 0

The following will decrease reaction rate

  • decrease temperature  
  • decrease concentration
<h3>Further explanation  </h3>

The reaction rate (v) shows the change in the concentration of the substance (changes in addition to concentrations for reaction products or changes in concentration reduction for reactants) per unit time.  

Can be formulated:  

Reaction: aA ---> bB  

\large{\boxed{\boxed{\bold{v~=~-\frac{\Delta A}{\Delta t}}}}  

or  

\large{\boxed{\boxed{\bold{v~=~+\frac{\Delta B}{\Delta t}}}}  

A = reagent  

B = product  

v = reaction rate  

t = reaction time  

In chemical reactions several factors influence :

  • 1. Temperature

The temperature of the reaction that is raised will cause the particles to move more actively so that collisions between particles will become more frequent so that the speed of chemical reactions will be greater

  • 2. Pressure

Addition of pressure will increase the concentration because the volume is reduced, a greater concentration will accelerate the reaction

  • 3. Concentration

The greater the concentration, the more substances dissolved and involved in the reaction, thereby increasing the speed of the reaction

  • 4. Stirring

The mechanical force applied to the solution that reacts will cause more collisions to accelerate the reaction

  • 5 Catalysts

Addition of a catalyst to accelerate the reaction without reaction with reactant substances

So the following will decrease reaction rate

  • decrease temperature  
  • decrease concentration

<h3>Learn more </h3>

the rate of a reaction

brainly.com/question/7127331

the rate of a reaction can be increased

brainly.com/question/6710438

Endothermic and exothermic reactions

brainly.com/question/8552336

the rate of a reaction can be increased2

brainly.com/question/6721185

zavuch27 [327]3 years ago
6 0

The following quantities will effect the reaction rate as follows:

1. On increasing Concentration of the reactant: Rate of the reaction will increases.

2. On increasing pressure : Increases the rate of reaction to the side where there are fewer number of molecules.

3.On increasing temperature of an endothermic reaction: Increases the rate of reaction

4. On decreasing temperature of an endothermic reaction: Increases the rate of reaction.

So the answer is increase pressure, decrease temperature, increase concentration will increases the rate of the reaction.

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Answer:

\large \boxed{1.447 \times 10^{23}\text{ molecules Cu(OH)}_{2 }}

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\text{No. of molecules} = \text{0.240 36 mol Cu(OH)}_{2} \times \dfrac{6.022 \times 10^{23}\text{ molecules Cu(OH)}_{2}}{\text{1 mol Cu(OH)}_{2}}\\\\= 1.447 \times 10^{23}\text{ molecules Cu(OH)}_{2}\\\text{The sample contains $\large \boxed{\mathbf{1.447 \times 10^{23}}\textbf{ molecules Cu(OH)}_{\mathbf{2}}}$}

6 0
3 years ago
I begin the reaction with 0.45 g of beryllium. If my actual yield of beryllium chloride (mm = 79.91 g/mol) was 3.5 grams, what w
trasher [3.6K]

The percentage of yield was 777.78%

<u>Explanation:</u>

We have the equation,

Be [s]  +  2 HCl [aq]  →  BeCl 2(aq]  + H 2(g]  ↑ Be (s]  + 2 HCl [aq]  →  BeCl 2(aq]  + H 2(g] ↑

To find the percent yield we have the formula

Percentage of Yield= what you actually get/ what you should theoretically get  x 100

                                   =3.5 g/0.45 g 100

                                    = 777.78 %

The percentage of yield was 777.78%

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kvv77 [185]
<span>the bonds in iron(III) oxide are more ionic</span>
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3 years ago
Read 2 more answers
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