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Karolina [17]
3 years ago
9

A smaller square is within a larger square as shown below. A point is chosen at random in the larger square. What percent of the

time will be in the BLUE region? Round to the nearest tenth of a percent.

Mathematics
1 answer:
Bas_tet [7]3 years ago
4 0

Answer: 84.5%

Step-by-step explanation:

15.2 × 15.2 = 231.04 cm² (area of the entire large square)

5.98 × 5.98 = 35.76 cm² (area of the small square)

large square - small square = area of the blue region

231.04 - 35.76 = 195.28 cm² (area of the blue region)

\frac{area of the blue region}{large square} = percentage of time that the point will be in the blue region

\frac{195.28}{231.04} = 0.845 --> 84.5%

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If ?2000 is placed into a bank account that pays 3% compound interest per year , how much will be in the account after 2 years ?
Elodia [21]

Answer:

Step-by-step explanation:

A=P(1+r/n)^t*n

A=2000(1+.03)^2

A=2000(1.03)^2

A=2000(1.0609)

A=2121.80

Since it’s per year I didn’t divide 1 by .03 or multiply it by 2 since it would end in the same equation. If you were to do semiannually or any other payment period, the process would have been nessassary.

Hope this helps!

3 0
3 years ago
How do you combine like terms of -8(r-2) + 6(r-2) ??? Will mark brainliest if the answer is right.
solmaris [256]

Answer:

-2r+4

Step-by-step explanation:

-8(r-2)+6(r-2)

Distribute:

(-8)(r)+(-8)(-2)+(6)(r)+(6)(-2)\\-8r+16+6r+-12

Combine like terms:

(-8r+6r)+(16+-12)\\-2r+4

-2r + 4 is your answer.

6 0
3 years ago
5X23X2 using properties to find the sum or product
lianna [129]
5\cdot 23 \cdot 2=(5\cdot 2)\cdot 23 = 10\cdot 23=230


4 0
3 years ago
If a fair die is rolled 7 times, what is the probability, rounded to the nearest thousandth, of getting at most 1 two?
hjlf

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0.67

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4 0
2 years ago
The length of human pregnancies from conception to birth varies according to an approximately normal distribution with a mean of
Varvara68 [4.7K]

Answer:

A) 68.33%

B) (234, 298)

Step-by-step explanation:

We have that the mean is 266 days (m) and the standard deviation is 16 days (sd), so we are asked:

A. P (250 x < 282)

P ((x1 - m) / sd < x < (x2 - m) / sd)

P ((250 - 266) / 16 < x < (282 - 266) / 16)

P (- 1 < z < 1)

P (z < 1) - P (-1 < z)

If we look in the normal distribution table we have to:

P (-1 < z) = 0.1587

P (z < 1) = 0.8413

replacing

0.8413 - 0.1587 = 0.6833

The percentage of pregnancies last between 250 and 282 days is 68.33%

B. We apply the experimental formula of 68-95-99.7

For middle 95% it is:

(m - 2 * sd, m + 2 * sd)

Thus,

m - 2 * sd <x <m + 2 * sd

we replace

266 - 2 * 16 <x <266 + 2 * 16

234 <x <298

That is, the interval would be (234, 298)

6 0
3 years ago
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