Answer:
1.2 102j
Explanation:
because it is the most important for me
Answer:
A. F=107.6nN
B. Repulsive
Explanation:
According to coulombs law, the force between two charges is express as
F=(Kq1q2) /r^2
If the charges are of similar charge the force will be repulsive and if they are dislike charges, force will be attractive.
Note the constant K has a value 9*10^9
Hence for a charge q1=7.10nC=7.10*10^-9, q2=4.42*10^-9 and the distance r=1.62m
If we substitute values we have
F=[(9×10^9) ×(7.10×10^-9) ×(4.42×10^-9)] /(1.62^2)
F=(282.4×10^-9)/2.6244
F=107.6×10^-9N
F=107.6nN
B. Since the charges are both positive, the force is repulsive
Answer:
C
Explanation:
becauase i just tooke the test
Answer:
Explanation:
Given:
Acceleration, a = -2.4 m/s^2
Acceleration due to gravity, g = 9.8 m/s^2
Sum of forces = 0
Fr + F = 0
Fr = µsl × m × g
Since, Fn = m × g
m × a = (- µsl × mg)
µsl = -a/g
= 2.4/9.8
= 0.245
