Molar mass of 13c = 13 grams
number of moles = mass / molar mass
therefore,
number of moles = 7 / 13
To know the number of atoms in 7/13 moles, we simply multiply the number of moles by Avogadro's number as follows:
number of atoms = (7/13) x 6.022 x 10^23 = 3.2426 x 10^23 atoms
Temperature, cloud cover and thunder are all examples of weather.
<h3><u>Explanation:</u></h3>
Weather is described as conditions that prevail for a short period of time and the above-mentioned factors change variably throughout the day. Cloud cover simply describes the clouds coverage in the sky. It is one factor that is used to describe weather conditions since the type of clouds indicates prevailing weather.
For example, the presence of cirrus means there will be a storm in 24 to 48 hours. Weather conditions characterized by thunder is said to be stormy and it also has other conditions such as lightning, wind and fast rain with heavy raindrops. Temperature affects the warmness and coldness of the air and its movement. Moreover, it also affects all other aspects of weather conditions.
For the reactants,
- The oxidation number of hydrogen = +1
- The oxidation number of oxygen = -2
- The oxidation number of arsenic = +5
- The oxidation number of carbon = +3
For the products,
- The oxidation number of hydrogen = +1
- The oxidation number of oxygen = -2
- The oxidation number of arsenic = +3
- The oxidation number of carbon = +4
Here, arsenic (+5 to +3) and carbon (+3 to +4) are the only oxidation numbers changing.
Note that an increase in oxidation number means electrons are lost. Thus oxidation is occurring, and a decrease in oxidation number means electrons are being gained, and thus reduction is occurring.
Also, the compound that contains the element being oxidized is the reducing agent, and the compound that contains the element being reduced is the oxidizing agent.
So, the answers are:
name of the element oxidized: Carbon
name of the element reduced: Arsenic
formula of the oxidizing agent: 
formula of the reducing agent: 
start the balancing by writing down how many atoms there are per element. we’ll use this as an example:
C3H8 + O2 --> H2O + CO2
C = 3 C = 1
H = 8 H = 2
O = 2 O = 3
balance the carbon first, as it is easiest to do. add a coefficient to the single carbon atom on the right of the equation to balance it with the 3 carbon atoms on the left of the equation:
C3H8 + O2 --> H2O + (3)CO2
now there are 3 carbon atoms on each side. however, when you do this, you multiply the amount of oxygen atoms you had. therefore, now, there are 6 carbon atoms in 3CO2, plus that other oxygen atom in H2O. you now have 7 O atoms instead of 3.
C = 3 C = 3
H = 8 H = 2
O = 2 O = 7
now let’s move on to the hydrogen atoms.
C3H8 + O2 --> H2O + 3CO2
you have 8 hydrogen atoms on the left side, and 2 on the right. in order to balance them, you have to multiply the right side’s hydrogen atoms by 4. 4(2) = 8.
C3H8 + O2 --> (4)H2O + 3CO2
now both hydrogen and carbon atoms are balanced. same amount on both sides. however, your oxygen atoms have changed due to the multiplying (right side). you now have 10 of them.
C = 3 C = 3
H = 8 H = 8
O = 2 O = 10
now we balance the oxygen atoms. multiply the left side of the equation’s oxygen atoms by 5. 5(2) = 10
C3H8 + (5)O2 --> 4H2O + 3CO2
the chemical equation is all balanced. basically, just multiply with numbers until it equals the same amount on both sides.
C = 3 C = 3
H = 8 H = 8
O = 10 O = 10
Answer:
The answer to your question is 0.54M
Explanation:
Data
Final concentration = ?
Concentration 1 = 0.850 M
Volume 1 = 249 ml = 0.249 l
Concentration 2 = 0.420 M
Volume 2 = 0.667 M
Process
1.- Calculate the number of moles in both solutions
Number of moles 1 = Molarity 1 x Volume 1
= 0.850 x 0.249
= 0.212
Number of moles 2 = Molarity 2 x Volume 2
= 0.420 x 0.667
= 0.280
Total number of moles = 0.212 + 0.280
= 0.492
2.-Calculate the final volume
Final volume = Volume 1 + Volume 2
Final volume = 0.249 + 0.667
= 0.916 l
3.- Calculate Molarity
Molarity = 0.492 / 0.916
Molarity = 0.54
