Answer:
2H+(aq) + 2OH-(aq) → 2H2O(l)
Explanation:
Step 1: The balanced equation
2HCl(aq)+Ca(OH)2(aq) → 2H2O(l)+CaCl2(aq)
This equation is balanced, we do not have the change any coefficients.
Step 2: The netionic equation
The net ionic equation, for which spectator ions are omitted - remember that spectator ions are those ions located on both sides of the equation - will.
2H+(aq) + 2Cl-(aq) + Ca^2+(aq) + 2OH-(aq) → 2H2O(l) + Ca^2+(aq) + 2Cl-(aq)
After canceling those spectator ions in both side, look like this:
2H+(aq) + 2OH-(aq) → 2H2O(l)
Answer:
C. 1 cubic foot of loose sand
Explanation:
For many objects having equal volume , surface area will be maximum
of the object which has spherical shape .
But when a sphere is broken into tiny small spheres , total surface area of all the small spheres will be more than surface area of big sphere .
Hence among the given option , surface area of loose sand will have greatest surface area . Loose sand is equivalent to small spheres .
The answer to ur question corresponds to the information u provided in option A.
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The answer is:
CO2 (g) + H2O ( I) > H2CO3 ( aq) H2CO3 ( aq) + NAOH ( aq) > NaCO3 (aq) + H2O ( I)
The reaction of potassium iodide with silver nitrate results in the formation of silver iodide as a precipitate.
<h3>What is a precipitate?</h3>
A precipitate is given as the solid deposition in the solution. It is formed as the product in the chemical reaction with the insolubility in the solution.
The reaction of KI with silver nitrate results in the formation of soluble potassium nitrate and insoluble silver iodide, which forms as the precipitate.
Thus, the reaction of potassium iodide with silver nitrate results in the formation of silver iodide as a precipitate.
Learn more about precipitate, here:
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