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katrin [286]
2 years ago
6

in 1990 Jamaica's population of 2,466,000 was expected to grow exponentially by 1.1% each year. what is the range of the exponen

tial function that decribes this growth​
Mathematics
1 answer:
Misha Larkins [42]2 years ago
7 0

Answer:

Initial population is 2,466,000 ( p0 )

Growth is 1.1% each year ( r=1.1

p(t)=p0(1+r)t

After 30 years, the population of Jamaica should be 3.42 million by that calculation, but it is only 2.95 million, so apparently that growth rate was a little high, or wasn’t sustained.

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Now Using quadratic formula to solve above equation we get;

x= \frac{-b \±\sqrt{b^2-4ac}} {2a}\\\\here \ \ a= 5,b=-4,c=-5\\\\x= \frac{-(-4) \±\sqrt{(-4)^2-4\times 5\times-5}} {2\times5}\\\\x=\frac{4 \±\sqrt{16+100}} {10}\\\\x=\frac{4 \±\sqrt{116}} {10}=x=\frac{4 \±2\sqrt{29}} {10}= x=\frac{2 \±\sqrt{29}} {5}\\ x \approx 1.5 \ or \ x = -0.7

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