Answer:
Explanation:
2NaNO₃ = 2NaNO₂ + O₂
NaNO₃ = NaNO₂ + 1/2 O₂
- 468 kJ -369 kJ 0 kJ
enthalpy of decomposition reaction
= - 369 - ( - 468 ) kJ
= 99 kJ / mol .
Answer:
I guess A, I am not sure...
Formula for Barium Nitrate = Ba(NO3)2
Thus based on stoichiometry:
1 mole of Ba(NO3)2 contains 2 moles of NO3-
Therefore, concentration of nitrate ion NO3- would be = 2*0.240 = 0.480 M
Use the relation:
V1M1 = V2M2
V1 = V2M2/M1 = 0.500 L * 0.0800/0.480 = 0.0833 L
Thus, 0.0833 L or 83.3 ml solution of Ba(NO3)2 would be required.
The reactants are A: Carbon Dioxide and water
B) synthetic reactions. There is no such thing as "synthetic reactions" but synthesis reactions.