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lianna [129]
3 years ago
15

What happens when bonds are broken?

Chemistry
1 answer:
gogolik [260]3 years ago
6 0

Answer:

hi Adavaith is it okay for the

Explanation:

using computer

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The potential difference across the terminals of a battery of e.m.f. 12 V and internal resistance 2 ohm drops to 10 V when it is
lesantik [10]

Explanation:

The given data is as follows.

      E.m.f = 12 V,        Voltage = 10 V,        Resistance = 2 ohm

Hence, calculate the current as follows.

          I = \frac{E - V_{t}}{r_{int}}

Putting the given values into the above formula as follows.

         I = \frac{E - V_{t}}{r_{int}}

           = \frac{12 - 10}{2}

           = 1 A

Atomic weight of copper is 63.54 g/mol. Therefore, equivalent weight of copper is \frac{M}{2}.

That is,          \frac{M}{2}

                = \frac{63.54 g/mol}{2}

Hence, electrochemical equivalent of copper is as follows.

                   Z = (\frac{E}{96500}) g/C

                       = (\frac{63.54 g/mol}{2 \times 96500}) g/C

                       = 3.29 \times 10^{-4} g/C

Therefore, charge delivered from the battery in half-hour is calculated as follows.

                     It = Q

                       = 1 \times \frac{1}{2} \times 60 times 60  

                       = 1800 C

So, copper deposited at the cathode in half-an-hour is as follows.

                     M = ZQ

                = 3.29 \times 10^{-4} g/C \times 1800 C

                = 0.5927 g

Thus, we can conclude that 0.5927 g of copper is deposited at the cathode in half an hour.

8 0
3 years ago
Which chemical formula represents both an element and a molecule?
victus00 [196]

Answer:

Explanation:

element - a basic substance that can't be simplified (hydrogen, oxygen, gold, etc...) molecule - two or more atoms that are chemically joined together (H2, O2, H2O, C6H12O6, etc...) compound - a substance that contains more than one element (H2O, C6H12O6, etc...)

5 0
2 years ago
Bromo-4-fluorohexane has two chiral carbon atoms; therefore, the maximum number of possible stereoisomers that can be formed is
Zepler [3.9K]

Here we have to draw the four isomers of the compound 3-bromo-4-fluorohexane.

The four isomers of the compound is shown in the figure.      

In an organic molecule the chiral -C center is that where four (4) different groups are present. In 3-bromo-4-fluorohexane the 3 and 4 positions are chiral centers. The possible isomers of a molecule can be obtained from the formula 2n. As here 2 chiral centers are present thus number of stereoisomers will be 2×2 = 4.

The four different isomers as shown in the figure are 3R-, 4R-; 3S-, 4S; 3R, 4S and 3S-, 4R- 3-bromo-4-fluorohexane.

In the 3-bromo-4-fluorohexane the functional groups are -Br, C₂H₅, -C₃H₆F and -H for 3-position and -F, -C₂H₅, -C₃H₆ and -H for 4-position respectively.

The priority of the -3 position will be Br > C₃H₆F > C₂H₅ > H and for -4 position F > C₃H₆Br > C₂H₅ > H. If the rotation from the higher priority group to lower is clockwise and anticlockwise then the S- and R- notation are used respectively. However if the -H atom is present at the horizontal position then the notation will be reverse.

Thus the four isomers of the compound is shown.      

4 0
3 years ago
What would the molecule CH₄ be classified as?
larisa [96]

Answer:

Alkane

Explanation:

Definition of Alkane "any of the series of saturated hydrocarbons including methane, ethane, propane, and higher members. (google dictionary)"

CH4 is methane.

6 0
3 years ago
When 1.95 g of co(no3)2 is dissolved in 0.350 l of 0.220 m koh, what are [ co2+], [ co(oh)42−], and [ oh−] if kf of co(oh)42− =
Airida [17]
Mass of Co(NO₃)₂ = 1.95 g
V KOH = 0.350 L
[KOH] = 0.220 M
Kf = 5.0 x 10⁹
molar mass of Co(NO₃)₂ = 182.943 g/mol
so [Co(NO₃)₂] = 1.95 / (0.350 * 182.943) = 0.03045 M
[Co²⁺] = 0.03045 M
[OH⁻] = 0.22 M
chemical reaction:
             Co²⁺(aq) + 4 OH⁻    ⇄      Co(OH)₄²⁻
I (M)      0.03045      0.22                   0
C (M)   - 0.03045   - 4 (0.03045)      0.03045
E (M)       - x         0.22 - 4(0.03045)   0.03045
                              = 0.0982
Kf  = [Co(OH)₄²⁻] / [Co⁺²][OH⁻]⁴
5.0 x 10⁹ = (0.03045) / x (0.0982)⁴
x = 6.5489 x 10⁻⁸
at equilibrium:
[Co²⁺] = 6.54 x 10⁻⁸
[OH⁻] = 0.0982 M
[Co(OH)₄²⁻] = 0.03045 M



4 0
3 years ago
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