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kodGreya [7K]
3 years ago
5

I am giving brainliest, IF WORK IS SHOWN. please help.

Mathematics
1 answer:
lord [1]3 years ago
8 0

Answer:

-2/3

Step-by-step explanation:

The equation of the series:

a_n = \frac{5-(n-1)}{3} \\a_n = \frac{6-n}{3}\\

Where a_n is the nth term and n is the number of terms.

Now let's calculate the partial sum. The equation for the partial sum should be: S_n = \frac{1}{2}(a_1 +a_n)

The first term is 5/3.

The 15th term according to our previous equation is:

a_{15} = \frac{6-15}{3} \\a_{15} = -3

Put all that together we get:

S_{15} = \frac{1}{2}(\frac{5}{3}+(-3))\\S_{15} = \frac{5}{6}-\frac{3}{2}\\S_{15} = -\frac{2}{3}

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The accompanying data came from a study of collusion in bidding within the construction industry. No. Bidders No. Contracts 2 6
viktelen [127]

Answer:

a)

The proportion of contracts involved at most five bidders is 0.667.

The proportion of contracts involved at least five bidders is 0.51.

b)

The  proportion of contracts involved  between five and 10 inclusive bidders is 0.5.

The  proportion of contracts involved  strictly between five and 10 bidders is 0.304.

Step-by-step explanation:

No. bidders    No. contracts     Relative frequency of contracts

2                         6                       6/102=0.0588

3                         20                     20/102=0.1961

4                         24                     24/102=0.2353

5                         18                       18/102=0.1765

6                         13                        13/102=0.1275

7                          7                          7/102=0.0686

8                          5                          5/102=0.049

9                          6                          6/102=0.0588

10                         2                           2/102=0.0196

11                          1                            1/102=0.0098

Total                  102

a)

We have to find proportion of contracts involved at most five bidders.

Proportion of at most 5= Relative frequency 2+ Relative frequency 3+ Relative frequency 4+ Relative frequency 5

Proportion of at most 5=0.0588+ 0.1961+0.2353+0.1765

Proportion of at most 5=0.6667

The proportion of contracts involved at most five bidders is 0.667.

proportion of at least five bidders= proportion≥5= 1- proportion less than 5

Proportion less than 5=0.0588+ 0.1961+0.2353=0.4902

proportion of at least five bidders=1-0.4902=0.5098

The proportion of contracts involved at least five bidders is 0.51

b)

We have to find proportion of contracts involved  between five and 10 inclusive bidders.

Proportion of contracts between five and 10 inclusive= Relative frequency 5+ Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9+ Relative frequency 10

Proportion of between five and 10 inclusive=0.1765 +0.1275 +0.0686 +0.049 +0.0588 +0.0196

Proportion of between five and 10 inclusive=0.5

The  proportion of contracts involved  between five and 10 inclusive bidders is 0.5

We have to find proportion of contracts involved  strictly between five and 10 bidders.

Proportion of contracts strictly between five and 10=  Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9

Proportion of strictly between five and 10=0.1275 +0.0686 +0.049 +0.0588

Proportion of strictly between five and 10=0.3039

The  proportion of contracts involved  strictly between five and 10 bidders is 0.304.

8 0
3 years ago
ASAP IM BEING TIME PLEASE!!
andre [41]

x° = 14°, y° = 14°; Use vertical and supplementary angles.

Step-by-step explanation:

The image of the answer is attached below.

In the given image two lines are parallel with transversal.

(9x + 12)° and ∠1 are vertically opposite angles.

Vertically opposite angles are equal.

∠1 = (9x + 12)°

Consecutive interior angles are supplementary.

(9x + 12)° + 3x° = 180°

⇒ 12x° = 168°

⇒ x° = 14°

Sum of the adjacent angles in a line are supplementary.

3x° + (4y – 10)° = 180°

⇒ 3(14)° + 4y° – 10° = 180°

⇒ 4y° = 148°

⇒ y° = 14°

Hence, x° = 14°, y° = 14°; Use vertical and supplementary angles.

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zubka84 [21]

Answer:

7 \times 58 = 406

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What fractional part of a day do you spend sleeping if you sleep 8 hours per day?
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Evaluate 5x + (-2x 2) for x = 3.<br><br> a. 21<br> b. -3<br> c. 11
Vladimir79 [104]

Answer:

C. 11

Step-by-step explanation:

Assuming the problem is 5x + (-2 * 2) with x equals 3.

5(3)+(-2*2)

15+(-4)=

15-4=11

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4 years ago
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