Given the radius is, r = 16 in,
The expression for the circumference of a circle is,
Therefore, we have,
Thus, the circumference of the circle is 100.48 in.
So we can start with the full of possibilities and eliminate them one by one.
The full set is {0,1,2,3,4,5,6,7,8,9}.
Now we know that any prime greater than 2 is odd as otherwise it would have 2 as a factor, so we can eliminate all of these digits that would be an even number, leaving:
{1,3,5,7,9}
We also know that any prime greater than 5 cannot be a multiple of 5 and that all numbers with 5 in the digits are a multiple of 5, so we can eliminate 5.
{1,3,7,9}
We know that 11,13,17 and 19 are all primes, so we cannot eliminate any more of these, leaving the set:
{1,3,7,9} as our answer.
Answer:
pi/4
Step-by-step explanation:
my answer is in the image above
Answer:
Tn = 4(-6)^n-1
Step-by-step explanation:
Write an explicit formula for an, the nth term of the sequence 4, -24, 144, ....
The sequence is a geometric sequence
Tn = ar^n-1
a is the first term
a = 4
r = -24/4 =144/-24
r = -6
Substitute
Tn = 4(-6)^n-1
