Answer:
Finding kth element is more efficient in a doubly-linked list when compared to a singly-linked list
Explanation:
Assuming that both lists have firs_t and last_ pointers.
For a singly-linked list ; when locating a kth element, you have iterate through a number of k-1 elements which means that locating an element will be done only in one ( 1 ) direction
For a Doubly-linked list : To locate the Kth element can be done from two ( directions ) i.e. if the Kth element can found either by traversing the number of elements before it or after it . This makes finding the Kth element faster because the shortest route can be taken.
<em>Finding kth element is more efficient in a doubly-linked list when compared to a singly-linked list </em>
The student should attempt to hold down the alt key, then enter 248 on the number pad and then release the alt key. Like so: °
Answer:
the study of the production and distribution of goods and services and their management is
Explanation:
thats all you said
Answer:
explain
Explanation:
sorry didn't understand a thing you said except copying and pasting documents
Answer:
LA15; LA22
LA16; LA31; LA32
LA169; LA126;
LA127; LA141
Explanation:
Given

Required
Course sequence to satisfy the prerequisite
From the course prerequisite, we have:
and 
This means that LA15 and LA22 are the base courses, and they have no prerequisite. So, we have:
![[LA15; LA22]](https://tex.z-dn.net/?f=%5BLA15%3B%20LA22%5D)
LA16 and LA31 have LA15 as their direct course prerequisite. So, the sequence becomes
![[LA15 \to [LA16, LA31]; LA22]](https://tex.z-dn.net/?f=%5BLA15%20%5Cto%20%5BLA16%2C%20LA31%5D%3B%20LA22%5D)
To complete the sequence, we read each course and place them other their prerequisite.
<em>See attachment for complete tree</em>
<em></em>
From the tree, we have the sequence to be:
<em>LA15; LA22</em>
<em>LA16; LA31; LA32</em>
<em>LA169; LA126;</em>
<em>LA127; LA141</em>
<em />