2 years ago

12-x 6 x+3 4 Solve for x

Mathematics

1 answer:

KATRIN_1 [288]2 years ago

8 0

Step-by-step explanation:

x = 0 (I don't know what the result of this operation is and I need it to know the x but that's what I can do)

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3 years ago

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3 years ago

Is domain of f(x,y) = 1 + (4 -y^2)^1/2 open, closed or neither<br><br> is it bounded or unbounded?

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Answer:

Closed and Bounded.

Step-by-step explanation:

Hi there!

1) Let's start by finding the values in which the function is defined. Remember that this can be rewritten:

$f(x,y) = 1 + (4 -y^2)^{\frac{1}{2}} \:id\:est\:f(x,y)=1+\sqrt{(4 -y^2)}$

Since every quadratic root are defined for values $\geq$ 0 then, this help us to understand that we need calculate what interval this Domain is:

$4-y^{2} \geq 0\\4-y^{2}-4\geq -4\\-y^{2}\geq-4 \\y^{2}\leq4\\-2\leq y\leq 2$

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