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Marina86 [1]
3 years ago
15

Two of the seven different pea traits examined by Mendel involved genes that we now know are linked. Knowing this, can you expla

in why Mendel was still able to use results from his crossing experiments to develop the principle of independent assortment?
Chemistry
1 answer:
ser-zykov [4K]3 years ago
4 0

Answer:: Mendel studied how traits are been passed from parents to offspring using seven features in peas, including height, flower color, seed color, and seed shape. To do this he divided the pea plant into short height and tall height. From this experiment he proposed a principle called independent assortment, which describes how different genes independently separate from one another when reproductive cells develop. Though this experiment was studied using gene formation in prokaryotic cell.

This principle of independent assortment is also seen in eukaryotic cells during meiosis.

Mendel proposed this principle because during cell formation of the offspring, each individual Gene from the parents will first separate to stand on its own before cross linking up together, which made the offspring look different from the parents. The principle of independent assortment does not criticize gene linkage, it only highlight how gene in the garments of the parents forms offspring, by sperating to assort independently.

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Radio waves travel at the speed of light which is 3.00 x 10^8. How many minutes does it take for a radio message to reach saturn
ryzh [129]

Answer:

43.89 min

Explanation:

Given that:-

The speed of light = 3.00\times 10^8\ m/s

The distance = 7.9\times 10^8\ km

The conversion of distance in km to distance into m is shown below as:-

1 km = 1000 m

So,

Distance = 7.9\times 10^8\times 1000\ m=7.9\times 10^{11}\ m

The relation between speed distance and time is shown below as:-

Speed=\frac{Distance}{Time}

Thus,

3.00\times 10^8=\frac{7.9\times 10^{11}}{Time}

300000000\times time=10^{11}\times \:7.9\ s

Time = 2633.33 seconds

Also, 1 s = 1/60 min

So,

Time=\frac{2633.33}{60}\ min=43.89\ min

3 0
3 years ago
S(s)+3F2(g)->SF6(g) how many mol of F2 are required to react completely with 2.30 mol of S?
Brilliant_brown [7]

Answer:  There are 6.9 mol of F_{2} are required to react completely with 2.30 mol of S.

Explanation:

The given reaction equation is as follows.

S(s) + 3F_{2}(g) \rightarrow SF_{6}(g)

Here, 1 mole of S is reaction with 3 moles of F_{2} which means 1 mole of S requires 3 moles of F_{2}.

Therefore, moles of F_{2} required to react completely with 2.30 moles S are calculated as follows.

1 mol S = 3 mol F_{2}\\2.30 mol S = 3 mol F_{2} \times 2.30 \\= 6.9 mol F_{2}

Thus, we can conclude that there are 6.9 mol of F_{2} are required to react completely with 2.30 mol of S.

3 0
3 years ago
Does Ag metal reacts with NaOH​
joja [24]

No Ag cannot react with NaOH because Ag is less reactive than Na in the reactivity series and can't displace it

5 0
3 years ago
If the a of a monoprotic weak acid is 2. 6×10−6, what is the ph of a 0. 33 m solution of this acid?
yawa3891 [41]

The pH of the monoprotic weak acid is 2.79.

<h3>What are weak acids?</h3>

The weak acids are the acids that do not fully dissociate into ions in the solution. Strong acids fully dissociate into ions.

The chemical reaction is HA(aq) ⇄ A⁻(aq) + H⁺(aq).

c (monoprotic acid) = 0.33 M.

Ka = 1.2·10⁻⁶

[A⁻] = [H⁺] = x

[HA] = 0.33 M - x

Ka = [A⁻]·[H⁺] / [HA]

2. 6 × 10⁻⁶ = x² / (0.33 M - x)

Solve quadratic equation: [H⁺] = 0.000524 M.

pH = -log[H⁺]

pH = -log(0.000524 M)

pH = 2.79

Thus,  the pH of the monoprotic weak acid is 2.79

To learn more about weak acids, refer to the below link:

brainly.com/question/13032224

#SPJ4

5 0
2 years ago
Two samples of a compound containing elements a and b are decomposed. the first sample produces 15 g of a and 35 g of
Alborosie

According to law of definite proportion, for a compound, elements always combine in fixed ratio by mass.

The formula of compound remains the same, let it be a_{x}b_{y} where, a and b are two different elements.

Since, the ratio of mass remains the same , calculate the ratio of masses of element a and b in both cases

\frac{a}{b}=\frac{15}{35}=\frac{10}{y}

rearranging,

y=\frac{10\times 35}{15}=23.3

Thus, mass of b produced will be 23.3 g.

3 0
3 years ago
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