(May not be 100% correct as there may be more context, but I hope this helps! Have a nice day!)
We can tell it won't be Claim 1 as Claim 1 compares a reddish-brown substance to a gray/white substance.
I am going to go with Claim 3 is most supported by the evidence because of the three descriptions of the different substances, none of them match.
Aspartic acid<span> (abbreviated as </span>Asp<span> or </span>D<span>; encoded by the codons [GAU and GAC]), also known as </span>aspartate<span> in its deprotonated form, is an α-amino acid that is used in the biosynthesis of proteins.</span><span> Similar to all other amino acids it contains an amino group and a carboxylic acid. Its α-amino group is in the protonated −NH+3 form under physiological conditions, while its α-carboxylic acid group is deprotonated −COO</span>−<span> under physiological conditions. Aspartic acid has an acidic side chain (CH</span>2<span>COOH) which reacts with other amino acids, enzymes and proteins in the body.</span>
Answer:
Hi there!
Your answer is
Mass: 12
&
Electrons:5
Explanation:
The electrons in a neutral atom is the same as the # of Protons!
Answer:
141 mL is the volume of a 2.30 mol/L solution of Na₂CO₃ that contains 0.325 mol of solute.
Explanation:
Molarity is a measure of concentration of a solution that indicates the amount of moles of solute that appear dissolved in each liter of the mixture.
So 2.30 mol / L indicates that 2.30 moles dissolve in 1 L of solution. You want to know in what volume is contained 0.325 mol of solute. For this you apply the following rule of three: if 2.30 moles of solute are present in 1 L of solution, 0.325 moles in how much volume is it?

volume= 0.141 L
Being 1L=1000 mL, then 0.141 L=141 mL
<u><em>141 mL is the volume of a 2.30 mol/L solution of Na₂CO₃ that contains 0.325 mol of solute.</em></u>