Answer:
2.4 moles of oxygen are needed to react with 87 g of aluminium.
Explanation:
Chemical equation:
4Al(s) + 3O₂(l) → 2AlO₃(s)
Given data:
Mass of aluminium = 87 g
Moles of oxygen needed = ?
Solution:
Moles of aluminium:
Number of moles of aluminium= Mass/ molar mass
Number of moles of aluminium= 87 g/ 27 g/mol
Number of moles of aluminium= 3.2 mol
Now we will compare the moles of aluminium with oxygen.
Al : O₂
4 : 3
3.2 : 3/4×3.2 = 2.4 mol
2.4 moles of oxygen are needed to react with 87 g of aluminium.
Is a compound that went through a chemicAl change
A fish is swimming at a constant rate toward the ocean floor. The equation y = −7x − 3 can be used to represent this situation, where y is the depth of the fish in meters below sea level and x is the number of seconds the fish has been swimming. Which statement best describes the depth of the fish, given this equation?
From a starting position of 7 meters below sea level, the fish is descending 3 meters per second.
B From a starting position of 7 meters below sea level, the fish is ascending 3 meters per second.
C From a starting position of 3 meters below sea level, the fish is descending 7 meters per second
Explanation:
Air has a heat capacity of about 700 Joules per kg per °K and a density of just 1.2 kg/m3, so its initial energy would be 700 x 1 x 1.2 x 293 = 246,120 Joules
