Im sorry i dont know im sure someone will
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132 grams x (1 mol / 44 grams) = 3 moles
<span>3 moles X (22.4 L/ 1 mol) = 67.2 </span><span>L</span>
Answer:
<u>= 2.2 g pf S. produced</u>
Explanation:
Balanced Reaction equation:
→ 
1 mole of H2S - 34.1g
? moles - 3.2g
= 3.2/34.1 =<u> 0.09 moles of H2S</u>
Also,
1 mole of S02 - 64.07 g
? moles - 4.42g
= 4.42/64.07 <u>= 0.069 moles of SO2</u>
<u />
<em>Meaning SO2 is the limiting reagent</em>
Finally, 3 moles of S - 32g of sulphur
0.069 mole = ? g of Sulphur
= 0.069 x 32
<u>= 2.2 g pf S.</u>
Answer:
pH = 4.17
Explanation:
According to the molar concentration you stated, pH of the solution is: 4.17
Remember that pH = - log [H⁺]
and [H⁺] = 10^-pH
When:
pH > 7 → Basic solution
pH = 7 → Neutral solution
pH < 7 → Acid solution