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Fudgin [204]
2 years ago
5

BEST ANSWER WILL BE MARKED BRAINIEST

Chemistry
2 answers:
ehidna [41]2 years ago
7 0

Answer:

photosynthesis occurs so the plants can create energy from carbon dioxide and sunlight.  

Explanation:

so basiclly it occurs so the plants can create energy to stay alive.

AleksandrR [38]2 years ago
7 0

Answer:

Explanation:

photosynthesis occurs basically to help plants get light in order to produce its necessary daily production of nutrients needed for animals to get carbohydrates froms which is eaten by animals since it gives energy. so basically photosynthesis--> energy --> carbs for mammals to eat!

the green colour reflects off the plant so it is not absorbed by the chloroplasts  rather all colours are absorbed just not green.

and every organic material on earth is produced by these cells which convert energy from the sun into nutrient filled plants.. its essential for the CO2 cycle ,  and since they conduct photo synthesis they are lowest level in the food chain so basically its important since they create nutrients for our plants.

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One mole of copper equals about how many atoms?
Arlecino [84]

One mole of copper equals 6.02 × 10^23 atoms. The answer is letter C. This follows the Avogaro’s law wherein 1 mole of a substance is equal to 6.02 x 10^23 atoms, formula units or molecules. This is applicable to all substances. 

8 0
3 years ago
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Use the given data at 500 K to calculate ΔG°for the reaction
Anton [14]

Answer : The  value of \Delta G^o for the reaction is -959.1 kJ

Explanation :

The given balanced chemical reaction is,

2H_2S(g)+3O_2(g)\rightarrow 2H_2O(g)+2SO_2(g)

First we have to calculate the enthalpy of reaction (\Delta H^o).

\Delta H^o=H_f_{product}-H_f_{reactant}

\Delta H^o=[n_{H_2O}\times \Delta H_f^0_{(H_2O)}+n_{SO_2}\times \Delta H_f^0_{(SO_2)}]-[n_{H_2S}\times \Delta H_f^0_{(H_2S)}+n_{O_2}\times \Delta H_f^0_{(O_2)}]

where,

\Delta H^o = enthalpy of reaction = ?

n = number of moles

\Delta H_f^0 = standard enthalpy of formation

Now put all the given values in this expression, we get:

\Delta H^o=[2mole\times (-242kJ/mol)+2mole\times (-296.8kJ/mol)}]-[2mole\times (-21kJ/mol)+3mole\times (0kJ/mol)]

\Delta H^o=-1035.6kJ=-1035600J

conversion used : (1 kJ = 1000 J)

Now we have to calculate the entropy of reaction (\Delta S^o).

\Delta S^o=S_f_{product}-S_f_{reactant}

\Delta S^o=[n_{H_2O}\times \Delta S_f^0_{(H_2O)}+n_{SO_2}\times \Delta S_f^0_{(SO_2)}]-[n_{H_2S}\times \Delta S_f^0_{(H_2S)}+n_{O_2}\times \Delta S_f^0_{(O_2)}]

where,

\Delta S^o = entropy of reaction = ?

n = number of moles

\Delta S_f^0 = standard entropy of formation

Now put all the given values in this expression, we get:

\Delta S^o=[2mole\times (189J/K.mol)+2mole\times (248J/K.mol)}]-[2mole\times (206J/K.mol)+3mole\times (205J/K.mol)]

\Delta S^o=-153J/K

Now we have to calculate the Gibbs free energy of reaction (\Delta G^o).

As we know that,

\Delta G^o=\Delta H^o-T\Delta S^o

At room temperature, the temperature is 500 K.

\Delta G^o=(-1035600J)-(500K\times -153J/K)

\Delta G^o=-959100J=-959.1kJ

Therefore, the value of \Delta G^o for the reaction is -959.1 kJ

3 0
3 years ago
This is for a study guide, I can't figure it out!
miskamm [114]
<span>The answer is "D" where the number of collisions per unit area is reduced by one-half. Drawing back on the piston means the volume is increased. The pressure is reduced. There are fewer collisions when the pressure is reduced.</span>
3 0
3 years ago
What does the 3 indicate in 1s22s22p63s1?
Dahasolnce [82]
The 3 indicates the third electron shell. (Which has only 1 electron in it in this configuration)

Hope this helps! :)
6 0
3 years ago
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What groups are Cl and F in
Nikitich [7]

Answer:

Halogens

Explanation:

5 0
3 years ago
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