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Phoenix [80]
3 years ago
6

Using the reaction below determine the amount of Sulfur proceduced in grams (this is a limiting reaction question) 2 H2S + SO2 -

> 3 S + H2O 3.26g of dihydrogen sulfide react with 4.42 g of sulfur dioxide
Chemistry
1 answer:
marusya05 [52]3 years ago
7 0

Answer:

<u>= 2.2 g pf S. produced</u>

Explanation:

Balanced Reaction equation:

2H_{2} S + SO_{2} →  3S + 2H_{2} O

1 mole of H2S - 34.1g

? moles - 3.2g

= 3.2/34.1 =<u> 0.09 moles of H2S</u>

Also,

1 mole of S02 - 64.07 g

? moles - 4.42g

= 4.42/64.07 <u>= 0.069 moles of SO2</u>

<u />

<em>Meaning SO2 is the limiting reagent</em>

Finally, 3 moles of S -  32g of sulphur

0.069 mole = ? g of Sulphur

= 0.069 x 32

<u>= 2.2 g pf S.</u>

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