Question

What is an equation of the line that passes through the point ( − 1 , − 3 ) and is perpendicular to the line x − 2 y = 14? pls answer will mark you as brainiest

Answer 1

Answer:

y = -2x - 5  or 2x + y = -5

Step-by-step explanation:

Let's find the slope of the given line.  

-2y = -x + 14

y = 1/2(x) -7

m = 1/2

The slope of a line perpendicular is the negative reciprocal of 1/2, which is -2

Now use the point-slope form of a line

y + 3 = -2(x + 1)

y + 3 = -2x - 2

y = -2x - 5  or 2x + y = -5

Answer 2

Answer:

y = -2x - 5

Step-by-step explanation:

First rewrite the second equation into y = mx + b format:

x - 2y = 14  

2y = x - 14

y = x/2 - 14/2 (Divide both sides by 2)

y = 1/2x - 7

A line perpendicular to another has the negative reciprocal slope

So the slope of our first equation is -2. (Flip 1/2 = 2, then take the opposite)

Plug in the points (-1, -3) for the x and y coordinates.

x (x coordinate) = -1

y (y coordinate) = -3

slope (m) = -2

-3 = -1(-2) + b

-3 = 2 + b

-3 - 2 = b

b = -5

The equation of the line is y = -2x - 5. Hope this helps! :)