Answer:
a. At pH 9, the product, p-nitrophenol, will be ionized, the solution will appear yellow in color, and thus can be monitored at the wavelength of maximum absorption for the phenolate ion which is 400nm
Explanation:
In alkaline phosphatase assay, the hydrolysis of p nitrophenyl phosphate to p nitrophenol happens. When the ph is 9, the product which is p nitrophenol would undergo ionization. The solution is going to appear to be of yellow and it can be monitored at a wavelength for maximum absorption of phenolate ions at 400nm.
Option A is the answer to the question.
The mass of 63 ml sample : 79.38 g
<h3>Further explanation</h3>
Given
20 ml and 25.2 g of glycerol
Required
The mass of 63 ml sample
Solution
Density is the ratio of mass per unit volume
Density formula:
Density of glycerol :
= m : V
= 25.2 g : 20 ml
= 1.26 g/ml
Mass of 63 ml sample :
= density x volume
= 1.26 g/ml x 63 ml
= 79.38 g
Sulfur, selenium, and tellurium
Answer:
1100 millimeters
Explanation:
1 mole of isopentyl alcohol = 22.4L = 22.4×1000 mL = 22,400L
0.050 moles of isopentyl alcohol = 0.050 × 22,400mL = 1120mL = 1100mL (to two significant figures)
I would say detailed drawing, but it is up to you
