All categories

2 years ago

What must happen before a body cell can begin mitotic cell division

1 answer:

3 0

Answer: The correct answer is- Replication of DNA ( deoxyribonucleic acid) must happen before a body cell can begin mitotic cell division.

Mitotic division is a type of cell division in which a parent cell divides two identical daughter cells ( through a series of five stages that is- prophase, metaphase, anaphase, telophase, and cytokinesis) having same number of chromosomes as that of the parental cell.

It occupies the second stage of cell cycle, the first being interphase ( which has three stages that is G1, S, and G2 phase). Replication of DNA takes place in the interphase ( particulary in the S phase) so that cell is ready to divide in the mitotic phase.

Thus, replication of DNA ( deoxyribonucleic acid) must happen before a body cell can begin mitotic cell division.

You might be interested in

Which statement below best describes mutations?

Studentka2010 [4]

Answer:

C. Mutations are a change in DNA or a chromosome and can be helpful, harmful or may have no affect.

Explanation:

Mutations are spontaneous random changes that occurs in the genetic make up of an organisms. Mutations are rare and their rate of occurrence is random.
Mutations may occur on the gene level known as gene mutations or at chromosome levels called chromosomal mutations.
Mutations may be beneficial, harmful or have no effect on a given organisms. Harmful mutations cause disorders that may lead to abnormality or death of an organisms. Beneficial mutations improve an organisms adaptability to the environment.

8 0

3 years ago

The name of an alkyl group that contains THREE carbon atoms is____

tester [92]

Answer:

The answer is "Propyl"

Explanation:

5 0

3 years ago

HELP!!!!!!! How many moles of AgNO3 must react to form 0.854 mol Ag? mol AgNO3

iris [78.8K]

There is 0.854 moles in AgNO3

4 0

3 years ago

Read 2 more answers

What’s the distance from the nucleus of an atom to its theoretical outer edge of electron orbits

ollegr [7]

Answer:

The range of atoms = (30-300 pm) depending upon the element

Explanation:

The Atomic radii of the atom is the distance from the center of the circle to the outermost orbital.

The center of the circle is the nucleus and the radii is the outermost boundary.

The actual size of the atom is decided on the basis of the Zeff . Also known as effective nuclear charge.

Zeff: It is the net positive charge felt by the outermost electron by the nucleus.

The value of Zeff depends upon the shielding constant. More the shielding less will be the Zeff . Hence the size of the atom increases.

Due to shielding the outermost electrons feel less pull of nucleus.

The greater the Zeff , the smaller the radius of the atom.

The formula used to calculate the atomic mass is :

$r_{n}=\frac{52.9n^{2}}{Z}$ pm

Here "pm"= picometers

$1 pm = 10^{-12}m$

The size of the smallest atom H-atom = 120 pm

The range of atoms = (30-300 pm)

4 0

2 years ago

Consider the following equilibrium: H2CO3+H2O = H3O+HCO3^-1. What is the correct equilibrium expression?

mylen [45]

Equilibrium expression is $Keq = \frac{[H3O+][HCO3^-]}{[H2CO3]}\\$

Explanation:

Equilibrium expression is denoted by Keq.

Keq is the equilibrium constant that is defined as the ratio of concentration of products to the concentration of reactants each raised to the power its stoichiometric coefficients.

Example -

aA + bB = cC + dD

So, Keq = conc of product/ conc of reactant

$Keq = \frac{[C]^c [D]^d}{[A]^a [B]^b}$

So from the equation, H₂CO₃+H₂O = H₃O+HCO₃⁻¹

$Keq = \frac{[H3O^+]^1 [HCO3^-]^1}{[H2CO3]^1 [H2O]^1}$

The concentration of pure solid and liquid is considered as 1. Therefore, concentration of H2O is 1.

Thus,

$Keq = \frac{[H3O+][HCO3^-]}{[H2CO3]}\\$

Therefore, Equilibrium expression is $Keq = \frac{[H3O+][HCO3^-]}{[H2CO3]}\\$

4 0

2 years ago