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MaRussiya [10]
3 years ago
11

The concentration of 1130+ in a solution is found to be 1.75 X 10-8 M 250C. Find [OH].

Chemistry
1 answer:
const2013 [10]3 years ago
5 0

Answer:

[OH] = 6.31 * 10^-7 M

Explanation:

Mathematically;

pH + pOH = 14

Mathematically;

pH = -log [H3O+]

also;

pOH = -log [OH]

From the question; [H3O+] = 1.75 * 10^-8 M

pH = -log [1.75 * 10^-8]

pH = 7.76

since pH is normally given to 1 decimal place

we can say pH = 7.8

Now;

pH + pOH = 14

pOH = 14-7.8

pOH = 6.2

now pOH = -log [OH]

[OH] = -antilog 6.2

[OH] = 6.31 * 10^-7 M

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Answer:

The standard cell potential is 2.00 V

Explanation:

<u>Step 1:</u> Data given

Cu is cathode because of higher EP

Al3++3e−→Al       E∘=−1.66 V     anode

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<u>Step 2:</u> Balance both equations

2*(Al → Al3+-3e−)       E∘=1.66 V    

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<u>Step 3:</u> The netto equation

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E∘cell = E∘cathode - E∘anode

E∘cell = E∘ Cu2+/Cu - E∘ Al3+/Al

E∘cell =0.340 V - (-1.66) = 2.00 V

The standard cell potential is 2.00 V

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