MgCI2 how many element ?

Chemistry

1 answer:

polet [3.4K]3 years ago

7 0

Answer:

2 elements magnesium(Mg) and chlorine (Cl)

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A silver rod and a SHE are dipped into a saturated aqueous solution of silver oxalate, Ag2C2O4, at 25°C. The measured potential

nika2105 [10]

Answer:

3.50*10^-11 mol3 dm-9

Explanation:

A silver rod and a SHE are dipped into a saturated aqueous solution of silver oxalate, Ag2C2O4, at 25°C. The measured potential difference between the rod and the SHE is 0.5812 V, the rod being positive. Calculate the solubility product constant for silver oxalate.

Ag2C2O4 --> 2Ag+ + C2O4 2-

So Ksp = [Ag+]^2 * [C2O42-]

In 1 L, 2.06*10^-4 mol of silver oxalate dissolve, giving, the same number of mol of oxalate ions, and twice the number of mol (4.12*10^-4) of silver ions.

So Ksp = (4.12*10^-4)^2 * (2.06*10^-4)

= 3.50*10^-11 mol3 dm-9

7 0

3 years ago

How many molecules of sugar are there in 1 can of soda?

Korvikt [17]

Answer:

$5.8\cdot 10^{22}$

Explanation:

Since no information was provided about the can of soda, let's take an example of 1 can of 12 fl oz (368 g) Coca-Cola.

The nutrition facts state that it contains 33 g of sugar. In order to calculate the number of molecules, we firstly need to know the molecular formula of sugar. Sugar can be represented by $C_{12}H_{22}O_{11}$ .

Our first step is to find the molar mass of sugar:

$M_{C_{12}H_{22}O_{11}} = 342.3 g/mol$

Secondly, dividing mass of sugar, $m = 33 g$ , by the molar mass will yield the number of moles of sugar:

$n_{C_{12}H_{22}O_{11}}=\frac{m}{M}$

Finally, multiplying moles by the Avogadro's constant will yield the number of molecules:

$N_{C_{12}H_{22}O_{11}}=n_{C_{12}H_{22}O_{11}}\cdot N_A =\frac{m}{M} \cdot N_A = \frac{33 g}{342.3 g/mol} \cdot 6.022 \cdot 10^{23} mol^{-1} = 5.8\cdot 10^{22}$