Answer:
The concentration of chloride ions in the final solution is 3 M.
Explanation:
The number of moles present in a solution can be calculated as follows:
number of moles = concentration in molarity * volume
In 100 ml of a 2 M KCl solution, there will be (0.1 l * 2mol/l) 0.2 mol Cl⁻
For every mol of CaCl₂, there are 2 moles of Cl⁻, then, the number of moles of Cl⁻ in 50 l of a 1.5 M solution will be:
number of moles of Cl⁻ = 2 * number of moles of CaCl₂
number of moles of Cl⁻ = 2 ( 50 l * 1.5 mol / l ) = 150 mol Cl⁻
The total number of moles of Cl⁻ present in the solution will be (150 mol + 0.2 mol ) 150.2 mol.
Assuming ideal behavior, the volume of the final solution will be ( 50 l + 0.1 l) 50.1 l. The molar concentration of chloride ions will be:
Concentration = number of moles of Cl⁻ / volume
Concentration = 150.2 mol / 50.1 l = 3.0 M
Methanol is the substance that can be broken down by chemical means, the remaining ones are elements.
Explanation:
A neutralization is a type of double replacement reaction. a salt is the product of an acid-base reaction and is a much broader term then common table salt.
Example:-
(i) HCl + NaOH ---> NaCl + HOH
(ii) H2SO4 + 2NH4OH ---> (NH4)2SO4 + 2HOH.
Answer:
<u>2</u><u>1</u><u>.</u><u>0</u><u>9</u><u> </u><u>g</u><u> </u><u>of</u><u> </u><u>AgCl</u>
Explanation:
Hopefully the picture is clear and the method is understandable.
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