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dimaraw [331]
3 years ago
15

How are theres over 2,500 different minerals why?

Chemistry
1 answer:
SOVA2 [1]3 years ago
5 0
A mineral occurs naturally, meaning that even though there are artificial substances that might be described as mineral-like they are not minerals
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7. Write the equation for the positron emission of barium-127.
ziro4ka [17]

The reaction is given by

\\ \rm\Rrightarrow {}^{127}_{56}Ba\longrightarrow {}^{0}_{+1}\beta+{}^{127}_{55}Cs

Barium goes underneath beta decay to form Ceaseum

  • Cs is very mellable element
  • It can melt on your hand
8 0
2 years ago
Which symbol represents a particle with a total of 10 electrons
vova2212 [387]
Al3+ is the answer. :)
7 0
3 years ago
Identify 2 ways to measure mass​
Likurg_2 [28]

Answer:

The two ways to measure mass are subtraction and taring.

8 0
3 years ago
If 15 g of C₂H₆ reacts with 60.0 g of O₂, how many moles of water (H₂O) will be produced?
IceJOKER [234]

Answer:

n_{H_2O}=1.5molH_2O

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

2C_2H_6 + 7O_2 \rightarrow 4CO_2 + 6H_2O

Next, we identify the limiting reactant by computing the available moles of ethane and the moles of ethane consumed by 60.0 grams of oxygen:

n_{C_2H_6}^{available}=15g*\frac{1mol}{30g} =0.50molC_2H_6\\n_{C_2H_6}^{reacted}=60.0gO_2*\frac{1molO_2}{32gO_2}*\frac{2molC_2H_6}{7molO_2} =0.536molC_2H_6

Thus, we notice there are less available moles, for that reason, the ethane is the limiting reactant. Finally, we can compute the produced moles of water by:

n_{H_2O}=0.50molC_2H_6*\frac{6molH_2O}{2molC_2H_6}\\\\n_{H_2O}=1.5molH_2O

Best regards.

5 0
3 years ago
Suppose that, from measurements in a microscope, you determine that a certain layer of graphene covers an area of 1.50μm2. Conve
irga5000 [103]
One \mu mis 10^{-6}m , hence one \mu m^2 is 10^{-12}m^2, thus 1.50\mu m^2 is 1.50\cdot10^{-12}\mu m^2
4 0
3 years ago
Read 2 more answers
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