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3 years ago

BONUS This Periodic Table was published several years ago. Which "new"

Chemistry

1 answer:

Olenka [21]3 years ago

7 0

Gallium, 31, Ga

Scandium, 21, Sc

Germanium, 32,Ge

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There are approximately 2 × 1022 molecules and atoms in each breath we take and the concentration of CO in the air is approximat

adoni [48]

Answer:

1.8x10¹⁷ molecules of CO are in each breath we take

Explanation:

Parts per million, ppm, is an unit of concentration in chemistry used for very diluted solutions.

<em>A 9ppm of X in a solution means in 1 million of molecules (1x10⁶) you have only 9 molecules of X.</em>

In a breath we have 2x10²² molecules and 9 ppm are CO. Thus, CO molecules in each breath are:

2x10²² molecules × (9 molecules CO / 1x10⁶ molecules) =

<h3>1.8x10¹⁷ molecules of CO are in each breath we take</h3>

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3 years ago

17.The formation of steam above a pot of water is an example of

sweet [91]

#1...Evaporation
#2....Gas

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3 years ago

The standard free-energy change for this reaction in the direction written is 23.8 kJ/mol. The concentrationsof the three interm

Natali [406]

Answer: The actual free-energy change for the reaction -8.64 kJ/mol.

Explanation:

The given reaction is as follows.

Fructose 1,6-bisphosphate $\rightleftharpoons$ Glyceraldehyde 3-phosphate + DHAP

For the given reaction, $\Delta G^{o}$ is 23.8 kJ/mol.

As we know that,

$\Delta G = \Delta G^{o} + RT ln Q$

Here, R = 8.314 J/mol K, T = $37^{o} C$

= (37 + 273) K

= 310.15 K

Fructose 1,6-bisphosphate = $1.4 \times 10^{-5}$ M

Glyceraldehyde 3-phosphate = $3 \times 10^{-6}$ M

DHAP = $1.6 \times 10^{-5}$ M

Expression for reaction quotient of this reaction is as follows.

Reaction quotient = $\frac{[DHAP][\text{glyceraldehyde 3-phosphate}]}{[/text{Fructose 1,6-bisphosphate}]}$

Q = $\frac{1.6 \times 10^{-5} \times 3 \times 10^{-6}}{1.4 \times 10^{-5}}$

= $3.428 \times 10^{-6}$

Now, we will calculate the value of $\Delta G$ as follows.

$\Delta G = \Delta G^{o} + RT ln Q$

= $23800 + 8.314 \times 310.15 \times ln(3.428 \times 10^{-6})$

= -8647.73 J/mol

= -8.64 kJ/mol

Thus, we can conclude that the actual free-energy change for the reaction -8.64 kJ/mol.

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3 years ago

The gas in the piston is being heated, and the piston has moved upward. The observation will be summarized in a row of the incom

densk [106]

Answer:

Explanation:

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3 years ago

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What is the hydro carbon?

jeka57 [31]

Hydrocarbon, to my knowledge is an organic compound consisting mainly of hydrogen and carbon. It is mainly found in petroleum and natural gas. Hope this helps!

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3 years ago

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**BONUS** This Periodic Table was published several years ago. Which "new"

BONUS This Periodic Table was published several years ago. Which "new"