Answer:
40.02 calories
Explanation:
V = 10 mL = 10g
we know t went <em>up</em> by 4°C, this is our ∆t as it is a change.
Formula that ties it together: Q = mc∆t
where,
Q = energy absorbed by water
m = mass of water
c = specific heat of water (constant)
∆t = temperature change
Q = (10 g) x (4.186 J/g•°C) x (4°C)
Q = 167.44 J
Joules to Calories:
167.44 J x 1 cal/4.184 J = 40.02 calories
(makes sense as in image it is close to the value).
Answer:
Explanation:
Here, we want to get the new volume of the gas
What we need to know is the law that connects volume and pressure at constant temperature
The law that supports this is the Boyle's law
It states that the volume of a given mass of gas is inversely proportional to its pressure at constant temperature
Mathematically, we can have this as represented as:
We can proceed mathematically to solve as follows;
Explanation:
The given data is as follows.
Concentration of acid, [HF] = 2 M
Concentration of salt, [NaF] = 0.472 M
Concentration of base, [NaOH] = 1.00 M
=
So, NaOH being a base will react with the acid that is, HF. And, according to Henderson-Hasselbalch equation we have he following.
pH =
Also, we known that
so,
= 3.1426
Hence, pH =
pH = 2.5155
Thus, we can conclude that pH of the solution is 2.5155.