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Afina-wow [57]
3 years ago
11

What is Thuy’s error?

Mathematics
2 answers:
tia_tia [17]3 years ago
8 0

Answer:

number b

Step-by-step explanation:

thuy should have written the ratio as 30/39

Gekata [30.6K]3 years ago
3 0
They should me number 29’
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What is the equation of a line that passes through (4, 3) and has a slope of 2?
Savatey [412]
Passes through (4,3) slope = 2

y - y1 = m(x - x1)
y - 3 = 2(x - 4)
y - 3 = 2x - 8
y = 2x - 5

C
4 0
1 year ago
Solve the equation <br>8(4- x) = 7x + 2<br>x=​
Jet001 [13]

Answer: x=2

Step-by-step explanation:

Expand.

32−8x=7x+2

Add 8x to both sides.

32=7x+2+8x

Simplify  7x+2+8x7x+2+8x  to  15x+215x+2.

32=15x+2

Subtract 22 from both sides.

32−2=15x

Simplify  32−2  to  30.

30=15x

Divide both sides by 15.

30/15=x

Simplify 30/15 to 2

2=x

Switch sides.

x=2

7 0
3 years ago
Your math teacher tells you that the next test is worth 100 points and contains 38 problems. Multiple-choice questions are worth
erastova [34]

Answer:

Most likely 8 word problems and 30 multiple choice

Step-by-step explanation:

8x5=40 and 30×2=60

40+60=100

7 0
3 years ago
A certain high school has 1,488 students. If you subtract the number of girls from boys you get 78. Let x be the number of boys
Dahasolnce [82]

Answer:

boys = 705

girls = 783

Step-by-step explanation:

We are to find the number of boys and girls in the school

the answer can be determined using simultaneous equation

x = boys

y = girls

y - x = 78  equation 1

y + x  = 1488 equation 2

subtract equation 1 from 2

2x = 1410

x = 1410/2 = 705

Substitute for x in equation 1

y - 705 = 78

y = 705 + 78 = 783

3 0
2 years ago
I need the whole solution
ddd [48]

Confused what the question is. Are you looking for the product or the zeroes?

If you are looking for the product, then:

Use foil to get: sec²(1) - sec²(-csc²) -1(1) -1(-csc²)

= sec² + sec²csc² - 1 + csc²

= sec²csc² + sec² + csc² - 1

= sec²csc² + 1 - 1 (NOTE: sec² + csc² = 1 is an identity)

= sec²csc²

Answer: sec²csc²

***************************************************

If you are looking for the zeroes, then:

Using the zero product property, set each factor equal to zero and solve.

<u>First factor:</u>

sec²Θ - 1 = 0

sec²Θ = 1

secΘ = 1, -1

remember that secΘ is \frac{1}{cos}

\frac{1}{cos} = 1 \frac{1}{cos} = -1

cross multiply to get:

cosΘ = 1 cosΘ = -1

use the unit circle (or a calculator) to find that Θ = 0 and π

<u>Second factor:</u>

1 - csc²Θ = 0

1 = csc²Θ

1, -1 = cscΘ

remember that cscΘ is \frac{1}{sin}

\frac{1}{sin} = 1 \frac{1}{sin} = -1

cross multiply to get:

sinΘ = 1 sinΘ = -1

use the unit circle (or a calculator) to find that Θ = \frac{\pi}{2} and \frac{3\pi}{2}

Answer: 0, π, \frac{\pi}{2} , \frac{3\pi}{2}

7 0
3 years ago
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