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inn [45]
3 years ago
14

1. ONE AND TWO HUNDREDTHS AS A DÉCIMAl AND FRACTION

Mathematics
1 answer:
astraxan [27]3 years ago
5 0

Answer:

1.02 as a decimal

1 and 1/50 as a fraction

Step-by-step explanation:

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7/8 minus1/4 minus 1/2
slava [35]

7/8 minus1/4 minus 1/2

7/8 - 1/4 - 1/2 =

(1 × 7)/(1 × 8) - (2 × 1)/(2 × 4) - (4 × 1)/(4 × 2) =

7/8 - 2/8 - 4/8 =

(7 - 2 - 4)/8 =

1/8

the answer is 1/8

7 0
3 years ago
What is the exact value of the expression √486−√24+√6? Simplify if possible.
nikitadnepr [17]
√486 - √24 + <span>√6 = 
</span>√81*6 - √4*6 + <span>√6 =
</span>9√6 - 2√6 + <span>√6 = 
8</span><span>√6

The correct answer is 8</span><span>√6. </span>
5 0
3 years ago
The following graph shows Taylor's journey home. The y-axis is the distance Taylor is from home. The x-axis shows the time of hi
pentagon [3]

Answer:

im sorry your image is not too good

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Find the value of each variable
aniked [119]

Answer:

Answer d)

a= 10*\sqrt{3} b=5*\sqrt{3}, c=15, and d=5

Step-by-step explanation:

Notice that there are basically two right angle triangles to examine: a smaller one in size on the right and a larger one on the left, and both share side "b".

So we proceed to find the value of "b" by noticing that it the side "opposite side to angle 60 degrees" in the triangle of the right (the one with hypotenuse = 10). So we can use the sine function to find its value:

b=10*sin(60^o)= 10*\frac{\sqrt{3} }{2} = 5*\sqrt{3}

where we use the fact that the sine of 60 degrees can be written as: \frac{\sqrt{3} }{2}

We can also find the value of "d" in that same small triangle, using the cosine function of 60 degrees:

d=10*cos(60^o)=10* \frac{1}{2} = 5

In order to find the value of side "a", we use the right angle triangle on the left, noticing that "a" s the hypotenuse of that triangle, and our (now known) side "b" is the opposite to the 30 degree angle. We use here the definition of sine of an angle as the quotient between the opposite side and the hypotenuse:

sin(30^o)= \frac{b}{a} \\a=\frac{b}{sin(30)} \\a=\frac{5*\sqrt{3} }{\frac{1}{2} } \\a= 10*\sqrt{3}

where we used the value of the sine function of 30 degrees as one half: \frac{1}{2}

Finally, we can find the value of the fourth unknown: "c", by using the cos of 30 degrees and the now known value of the hypotenuse in that left triangle:

c=10*\sqrt{3} * cos(30^o)=10*\sqrt{3} *\frac{\sqrt{3} }{2} \\c= 5*3=15

Therefore, our answer agrees with the values shown in option d)

6 0
3 years ago
Write the equation of a line that passes through point (2,3) and (0,9).
11Alexandr11 [23.1K]

Slope-intercept form:

y = mx + b        

"m" is the slope, "b" is the y-intercept (the y value when x = 0) or (0,y)


To find "m", you can use the slope formula and plug in the two points:

(2,3) = (x₁ , y₁)

(0,9) = (x₂ , y₂)


m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

m=\frac{9-3}{0-2}

m=\frac{6}{-2}

m = -3


y = -3x + b

To find "b", you can plug in one of the points into the equation (however they already gave you the y-intercept (0,9) or 9)


(2,3)

y = -3x + b

3 = -3(2) + b

3 = -6 + b

9 = b


y = -3x + 9


3 0
3 years ago
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