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2 years ago

1. ONE AND TWO HUNDREDTHS AS A DÉCIMAl AND FRACTION

Mathematics

1 answer:

astraxan [27]2 years ago

5 0

Answer:

1.02 as a decimal

1 and 1/50 as a fraction

Step-by-step explanation:

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Nicki has 30 pencils. for every green pencil, she has 5 purple pencils. how many pencils of of each color could she have

Hatshy [7]

Answer:

Step-by-step explanation:

(1) P = 5G

(2) G + P = 30

Substituting (1) into (2) gives:

G + 5G = 30

6G = 30

G =5

So there are 5 green pencils.

Now using that in (1) gives us P = 5 x 5 = 25

So there are 5 green pencils and 25 purple pencils.

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2 years ago

The base of a 50-ft ladder that is leaning against a building is placed 35 ft away from the bottom of a building. What angle doe

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3 years ago

In a picture, there are 40 monkeys, and 60% of the monkeys are in the trees.

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The number of monkeys in the tree are 24.

<h3>What are percentages?</h3>

Percentage is the fraction of an amount expressed as a number out of hundred. The sign used to represent percentages is %.

<h3>How many monkey are in the tree?</h3>

Number of monkeys in the tree = percent x total number of monkeys

60% x 40

0.6 x 40 = 24

To learn more about percentages, please check: brainly.com/question/25764815

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2 years ago

Please help on number 15

borishaifa [10]

....................................................................

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2 years ago

Solve the following equation by factoring:9x^2-3x-2=0

olya-2409 [2.1K]

Answer:

The two roots of the quadratic equation are

$x_1= - \frac{1}{3} \text{ and } x_2= \frac{2}{3}$

Step-by-step explanation:

Original quadratic equation is $9x^{2}-3x-2=0$

Divide both sides by 9:

$x^{2} - \frac{x}{3} - \frac{2}{9}=0$

Add $\frac{2}{9}$ to both sides to get rid of the constant on the LHS

$x^{2} - \frac{x}{3} - \frac{2}{9}+\frac{2}{9}=\frac{2}{9}$ ==> $x^{2} - \frac{x}{3}=\frac{2}{9}$

Add $\frac{1}{36}$ to both sides

$x^{2} - \frac{x}{3}+\frac{1}{36}=\frac{2}{9} +\frac{1}{36}$

This simplifies to

$x^{2} - \frac{x}{3}+\frac{1}{36}=\frac{1}{4}$

Noting that (a + b)² = a² + 2ab + b²

If we set a = x and b = $\frac{1}{6}\right)$ we can see that

$\left(x - \frac{1}{6}\right)^2$ = $x^2 - 2.x. (-\frac{1}{6}) + \frac{1}{36} = x^{2} - \frac{x}{3}+\frac{1}{36}$

$\left(x - \frac{1}{6}\right)^2=\frac{1}{4}$

Taking square roots on both sides

$\left(x - \frac{1}{6}\right)^2= \pm\frac{1}{4}$

So the two roots or solutions of the equation are

$x - \frac{1}{6}=-\sqrt{\frac{1}{4}}$ and $x - \frac{1}{6}=\sqrt{\frac{1}{4}}$

$\sqrt{\frac{1}{4}} = \frac{1}{2}$

So the two roots are

$x_1=\frac{1}{6} - \frac{1}{2} = -\frac{1}{3}$

and

$x_2=\frac{1}{6} + \frac{1}{2} = \frac{2}{3}$

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1 year ago