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2 years ago

1. ONE AND TWO HUNDREDTHS AS A DÉCIMAl AND FRACTION

Mathematics

1 answer:

astraxan [27]2 years ago

5 0

Answer:

1.02 as a decimal

1 and 1/50 as a fraction

Step-by-step explanation:

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The diameter of a small grain of sand is about 0.00002 meters, which can be written as 2•10^n

defon

Answer:

N = -5

Step-by-step explanation:

Move the decimal point right until it is right after the first significant figure.

N = 5

But wait! It's a decimal so it has to be negative.

N = -5

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3 years ago

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16/36 and 4/9 is it proportional or nonproportional

maw [93]

Answer:

proportional because you can divide 16 and 36 by four and get 4/9

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2 years ago

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F(x) = x2 - 8x - 20 What is the axis of symmetry, vertex, and y intercept

igor_vitrenko [27]

1. vertex is -4 because:

x^2-8x-20,

a=1, b=-8 , c=-20

use vertex form! -b/2a = -8/2(1) = -8/2 = -4.

2. axis of symmatry is the x which is also -4. The same steps go for the second one.

3. y intercept, I think the answer is -20. Im not sure for this one.

IF YOU LIKE THIS ANSWER PLEASE GIVE ME BRAINLIEST.

5 0

3 years ago

I dont know how to do graphing pls help

yarga [219]

Answer:

Solution: (-1, -1)

Step-by-step explanation:

y=4x+2

y=-4/3x-2

Solve by graphing.

First, you need to plot the y-intercept.

y=4x+2

2 will be your y-intercept.

Next, you plot your slope.

y=4x+2

From your y-intercept, you will go up 4 and right one space, if you run out of space go down 4 and left 1.

Now repeat the same steps for the next one.

y=-4/3x-2

Plot your y-intercept.

y=-4/3x-2

because your slope is negative you will go down 4 and right 3, if you run out of room go up 4 and left 3.

Then draw connecting lines and wherever the lines intersect, that's going to be your solution. In this case, the solution is (-1, -1).

Hope this helps :)

4 0

2 years ago

Read 2 more answers

Consider the following theorem and proof.Theorem: The number âš2 is not rational number.Proof: Let's suppose âš2 is a rational n

ololo11 [35]

Answer:

The statement "Both of the numbers a and b cannot be even." is justified by the fact that a/b is simplified lowest terms

Step-by-step explanation:

We need to show that the √2 is an irrational number.

And from the given steps of proof stated in the question, we need to find the assumption that justifies the fact : " Both of the number a and b cannot be even".

First take the given options :

Option a : √2 is a rational number

√2 being an rational or irrational has no relation of a and b to be even or odd. So, this option is rejected.

Option B : a/b is simplified lowest terms

This shows that a and b are not even because if a and b are even then a/b can be simplified in other lowest term.

Option c : √2 is a irrational number

Similarly, By using the inverse part of Option A, option c is also rejected.

Option d : The fact that b divides a evenly

This only shows that the a is even. This does not give any idea about b is even or not. So option D is also rejected.

Option E : The fact that a and b are whole numbers

This fact does not imply that the a and b are even or odd. So option E is also rejected.

Hence, The statement "Both of the numbers a and b cannot be even." is justified by the fact that a/b is simplified lowest terms

7 0

3 years ago