Complete question:
The growth of a city is described by the population function p(t) = P0e^kt where P0 is the initial population of the city, t is the time in years, and k is a constant. If the population of the city atis 19,000 and the population of the city atis 23,000, which is the nearest approximation to the population of the city at
Answer:
27,800
Step-by-step explanation:
We need to obtain the initial population(P0) and constant value (k)
Population function : p(t) = P0e^kt
At t = 0, population = 19,000
19,000 = P0e^(k*0)
19,000 = P0 * e^0
19000 = P0 * 1
19000 = P0
Hence, initial population = 19,000
At t = 3; population = 23,000
23,000 = 19000e^(k*3)
23000 = 19000 * e^3k
e^3k = 23000/ 19000
e^3k = 1.2105263
Take the ln
3k = ln(1.2105263)
k = 0.1910552 / 3
k = 0.0636850
At t = 6
p(t) = P0e^kt
p(6) = 19000 * e^(0.0636850 * 6)
P(6) = 19000 * e^0.3821104
P(6) = 19000 * 1.4653739
P(6) = 27842.104
27,800 ( nearest whole number)
The equation that models the number of funnel cakes and Oreos he can buy is 3.50x + 2.0y = 42
Data given;
- Cost of Oreos = $2.00
- The total amount spent = $42.00
<h3>What is the Equation</h3>
To solve this problem, we just need to write out an equation to show how he can spend $42.00 in the fair on Oreos and Cakes.
Let x represent the cakes
Let y represent the Oreos
The equation is thus;
The equation that shows the number of Cakes and Oreos can by is
3.50x + 2.0y = 42
Learn more about equation here;
brainly.com/question/13729904
Answer:
9 answer ok like floow on
Answer:
30
Step-by-step explanation:
40/100 x 50= 20
50-20=30
